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anonymous

  • one year ago

The perimeter of a rectangle is 64 units. Can the length x of the rectangle can be 20 units when its width y is 11 units?

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  1. anonymous
    • one year ago
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    please help me guys!

  2. anonymous
    • one year ago
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    well think what is the formula to find the perimeter?

  3. anonymous
    • one year ago
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    a+b+c?

  4. anonymous
    • one year ago
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    ?????

  5. anonymous
    • one year ago
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    P=2(l+w)

  6. anonymous
    • one year ago
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    i dont remember

  7. anonymous
    • one year ago
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    so now do the math with the formula

  8. anonymous
    • one year ago
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    can you give me the answer then we discuss it?

  9. texaschic101
    • one year ago
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    perimeter of rectangle is : P = 2L + 2W start subbing in : P = 64 L = 20 W = 11 if it comes out correct, then it can be a solution if it comes out incorrect, then it cannot

  10. anonymous
    • one year ago
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    here are my options

  11. anonymous
    • one year ago
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    No, the rectangle cannot have x = 20 and y = 11 because x + y ≠ 64 No, the rectangle cannot have x = 20 and y = 11 because x + y ≠ 32 Yes, the rectangle can have x = 20 and y = 11 because x + y is less than 64 Yes, the rectangle can have x = 20 and y = 11 because x + y is less than 32

  12. anonymous
    • one year ago
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    20+11*2=62

  13. anonymous
    • one year ago
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    no option has 62 as an answer

  14. texaschic101
    • one year ago
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    ok...lets sub P = 2L + 2W 64 = 2(20) + 2(11) 64 = 40 + 22 64 = 62....it cannot be true

  15. anonymous
    • one year ago
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    the= with a line through it means not = to. get it?

  16. anonymous
    • one year ago
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    yeah

  17. anonymous
    • one year ago
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    so whats the final answer from the options?

  18. anonymous
    • one year ago
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    I would say A

  19. anonymous
    • one year ago
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    ok thx!!!!

  20. anonymous
    • one year ago
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    no problem do you need more help?

  21. texaschic101
    • one year ago
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    It doesn't make much sense....x and y do not have to equal 64.....2x + 2y have to equal 64

  22. anonymous
    • one year ago
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    so whats the answer? texaschic

  23. anonymous
    • one year ago
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    yes buttons i could use some more help.

  24. anonymous
    • one year ago
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    k what do ya need

  25. texaschic101
    • one year ago
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    I think it is B

  26. triciaal
    • one year ago
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    |dw:1444324709211:dw|

  27. triciaal
    • one year ago
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    |dw:1444324811828:dw|

  28. texaschic101
    • one year ago
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    64 = 2x + 2(11) 64 = 2x + 22 64 - 22 = 2x 42 = 2x 21 = x the width would have to be 21 for this to be true so I guess it is A

  29. anonymous
    • one year ago
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    you guess?? thats not to reliable

  30. triciaal
    • one year ago
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    to match the answer choices p = 64 = 2(x + y) 32 = x + y when x = 20 and y = 11 x + y not = 31 so B

  31. triciaal
    • one year ago
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    correction not = 32 so B

  32. texaschic101
    • one year ago
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    thanks triciaal.....my mind was going blank....it is B, I see that now....because x + y would not have to equal 64 for it to be true

  33. anonymous
    • one year ago
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    I agree with triciaal

  34. anonymous
    • one year ago
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    so its b?

  35. texaschic101
    • one year ago
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    yes

  36. anonymous
    • one year ago
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    ya

  37. triciaal
    • one year ago
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    @texaschic101 welcome @david821 yes but do you see why?

  38. anonymous
    • one year ago
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    not really

  39. texaschic101
    • one year ago
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    x + y has to equal 32 for it to be correct....and if you do 20 + 11...that is 31, so it is not true

  40. anonymous
    • one year ago
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    its because x+y=31 not 32

  41. anonymous
    • one year ago
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    k

  42. triciaal
    • one year ago
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    I need a job as an online tutor so I wouldn't have to leave now.

  43. anonymous
    • one year ago
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    lol

  44. anonymous
    • one year ago
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    i need more help on one more quest

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