anonymous
  • anonymous
The perimeter of a rectangle is 64 units. Can the length x of the rectangle can be 20 units when its width y is 11 units?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
please help me guys!
anonymous
  • anonymous
well think what is the formula to find the perimeter?
anonymous
  • anonymous
a+b+c?

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anonymous
  • anonymous
?????
anonymous
  • anonymous
P=2(l+w)
anonymous
  • anonymous
i dont remember
anonymous
  • anonymous
so now do the math with the formula
anonymous
  • anonymous
can you give me the answer then we discuss it?
texaschic101
  • texaschic101
perimeter of rectangle is : P = 2L + 2W start subbing in : P = 64 L = 20 W = 11 if it comes out correct, then it can be a solution if it comes out incorrect, then it cannot
anonymous
  • anonymous
here are my options
anonymous
  • anonymous
No, the rectangle cannot have x = 20 and y = 11 because x + y ≠ 64 No, the rectangle cannot have x = 20 and y = 11 because x + y ≠ 32 Yes, the rectangle can have x = 20 and y = 11 because x + y is less than 64 Yes, the rectangle can have x = 20 and y = 11 because x + y is less than 32
anonymous
  • anonymous
20+11*2=62
anonymous
  • anonymous
no option has 62 as an answer
texaschic101
  • texaschic101
ok...lets sub P = 2L + 2W 64 = 2(20) + 2(11) 64 = 40 + 22 64 = 62....it cannot be true
anonymous
  • anonymous
the= with a line through it means not = to. get it?
anonymous
  • anonymous
yeah
anonymous
  • anonymous
so whats the final answer from the options?
anonymous
  • anonymous
I would say A
anonymous
  • anonymous
ok thx!!!!
anonymous
  • anonymous
no problem do you need more help?
texaschic101
  • texaschic101
It doesn't make much sense....x and y do not have to equal 64.....2x + 2y have to equal 64
anonymous
  • anonymous
so whats the answer? texaschic
anonymous
  • anonymous
yes buttons i could use some more help.
anonymous
  • anonymous
k what do ya need
texaschic101
  • texaschic101
I think it is B
triciaal
  • triciaal
|dw:1444324709211:dw|
triciaal
  • triciaal
|dw:1444324811828:dw|
texaschic101
  • texaschic101
64 = 2x + 2(11) 64 = 2x + 22 64 - 22 = 2x 42 = 2x 21 = x the width would have to be 21 for this to be true so I guess it is A
anonymous
  • anonymous
you guess?? thats not to reliable
triciaal
  • triciaal
to match the answer choices p = 64 = 2(x + y) 32 = x + y when x = 20 and y = 11 x + y not = 31 so B
triciaal
  • triciaal
correction not = 32 so B
texaschic101
  • texaschic101
thanks triciaal.....my mind was going blank....it is B, I see that now....because x + y would not have to equal 64 for it to be true
anonymous
  • anonymous
I agree with triciaal
anonymous
  • anonymous
so its b?
texaschic101
  • texaschic101
yes
anonymous
  • anonymous
ya
triciaal
  • triciaal
@texaschic101 welcome @david821 yes but do you see why?
anonymous
  • anonymous
not really
texaschic101
  • texaschic101
x + y has to equal 32 for it to be correct....and if you do 20 + 11...that is 31, so it is not true
anonymous
  • anonymous
its because x+y=31 not 32
anonymous
  • anonymous
k
triciaal
  • triciaal
I need a job as an online tutor so I wouldn't have to leave now.
anonymous
  • anonymous
lol
anonymous
  • anonymous
i need more help on one more quest

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