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anonymous
 one year ago
The perimeter of a rectangle is 64 units. Can the length x of the rectangle can be 20 units when its width y is 11 units?
anonymous
 one year ago
The perimeter of a rectangle is 64 units. Can the length x of the rectangle can be 20 units when its width y is 11 units?

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0please help me guys!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0well think what is the formula to find the perimeter?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so now do the math with the formula

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0can you give me the answer then we discuss it?

texaschic101
 one year ago
Best ResponseYou've already chosen the best response.0perimeter of rectangle is : P = 2L + 2W start subbing in : P = 64 L = 20 W = 11 if it comes out correct, then it can be a solution if it comes out incorrect, then it cannot

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0No, the rectangle cannot have x = 20 and y = 11 because x + y ≠ 64 No, the rectangle cannot have x = 20 and y = 11 because x + y ≠ 32 Yes, the rectangle can have x = 20 and y = 11 because x + y is less than 64 Yes, the rectangle can have x = 20 and y = 11 because x + y is less than 32

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0no option has 62 as an answer

texaschic101
 one year ago
Best ResponseYou've already chosen the best response.0ok...lets sub P = 2L + 2W 64 = 2(20) + 2(11) 64 = 40 + 22 64 = 62....it cannot be true

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0the= with a line through it means not = to. get it?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so whats the final answer from the options?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0no problem do you need more help?

texaschic101
 one year ago
Best ResponseYou've already chosen the best response.0It doesn't make much sense....x and y do not have to equal 64.....2x + 2y have to equal 64

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so whats the answer? texaschic

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yes buttons i could use some more help.

triciaal
 one year ago
Best ResponseYou've already chosen the best response.3dw:1444324709211:dw

triciaal
 one year ago
Best ResponseYou've already chosen the best response.3dw:1444324811828:dw

texaschic101
 one year ago
Best ResponseYou've already chosen the best response.064 = 2x + 2(11) 64 = 2x + 22 64  22 = 2x 42 = 2x 21 = x the width would have to be 21 for this to be true so I guess it is A

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0you guess?? thats not to reliable

triciaal
 one year ago
Best ResponseYou've already chosen the best response.3to match the answer choices p = 64 = 2(x + y) 32 = x + y when x = 20 and y = 11 x + y not = 31 so B

triciaal
 one year ago
Best ResponseYou've already chosen the best response.3correction not = 32 so B

texaschic101
 one year ago
Best ResponseYou've already chosen the best response.0thanks triciaal.....my mind was going blank....it is B, I see that now....because x + y would not have to equal 64 for it to be true

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I agree with triciaal

triciaal
 one year ago
Best ResponseYou've already chosen the best response.3@texaschic101 welcome @david821 yes but do you see why?

texaschic101
 one year ago
Best ResponseYou've already chosen the best response.0x + y has to equal 32 for it to be correct....and if you do 20 + 11...that is 31, so it is not true

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0its because x+y=31 not 32

triciaal
 one year ago
Best ResponseYou've already chosen the best response.3I need a job as an online tutor so I wouldn't have to leave now.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i need more help on one more quest
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