please help me guys!
well think what is the formula to find the perimeter?
i dont remember
so now do the math with the formula
can you give me the answer then we discuss it?
perimeter of rectangle is : P = 2L + 2W start subbing in : P = 64 L = 20 W = 11 if it comes out correct, then it can be a solution if it comes out incorrect, then it cannot
here are my options
No, the rectangle cannot have x = 20 and y = 11 because x + y ≠ 64 No, the rectangle cannot have x = 20 and y = 11 because x + y ≠ 32 Yes, the rectangle can have x = 20 and y = 11 because x + y is less than 64 Yes, the rectangle can have x = 20 and y = 11 because x + y is less than 32
no option has 62 as an answer
ok...lets sub P = 2L + 2W 64 = 2(20) + 2(11) 64 = 40 + 22 64 = 62....it cannot be true
the= with a line through it means not = to. get it?
so whats the final answer from the options?
I would say A
no problem do you need more help?
It doesn't make much sense....x and y do not have to equal 64.....2x + 2y have to equal 64
so whats the answer? texaschic
yes buttons i could use some more help.
k what do ya need
I think it is B
64 = 2x + 2(11) 64 = 2x + 22 64 - 22 = 2x 42 = 2x 21 = x the width would have to be 21 for this to be true so I guess it is A
you guess?? thats not to reliable
to match the answer choices p = 64 = 2(x + y) 32 = x + y when x = 20 and y = 11 x + y not = 31 so B
correction not = 32 so B
thanks triciaal.....my mind was going blank....it is B, I see that now....because x + y would not have to equal 64 for it to be true
I agree with triciaal
so its b?
x + y has to equal 32 for it to be correct....and if you do 20 + 11...that is 31, so it is not true
its because x+y=31 not 32
I need a job as an online tutor so I wouldn't have to leave now.
i need more help on one more quest