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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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so here is the basics if (x -2) is a factor x = 2 is a zero substitute f(2)=(2)3+7(2)2+14(2)+8 its a positive answer... so not a factor... try (x + 2) which means x - 2 is a zero substitute and check f(−2)=(−2)3+7(−2)2+14(−2)+8 if you evaluate it you'll get f(-2) = 0 so (x + 2) is a binomial factor. hope this makes sense
6x2 - 7x + 2
sorry, left out the first term

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Other answers:

its okay
|dw:1444325642741:dw|
i tried it out and got this: 6x^2 − 7x + 2
but I wasn't sure IF i was right or not
|dw:1444326511683:dw|
|dw:1444326737121:dw|
agree
ok, great- thank you!
Have one more question: did I do this one right?? What is the quotient when x^3 − 5x^2 + 3x − 8 is divided by x − 3?
sorry it took so long you are welcome
I got this: x2 − 2x − 3 − 17 over the quantity of x minus 3
and its okay! Thanks for helping:-)
and its x^2 not x2
|dw:1444326972888:dw||dw:1444327269013:dw|
use parenthesis in your answer or specify remainder I got the same
ok, thank you again!

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