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mckenzieandjesus
 one year ago
. Complete.
y2 + 15y + 56 = (y + 7)(y +mc0011.jpg)
–7
8
7
–8
mckenzieandjesus
 one year ago
. Complete. y2 + 15y + 56 = (y + 7)(y +mc0011.jpg) –7 8 7 –8

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mckenzieandjesus
 one year ago
Best ResponseYou've already chosen the best response.0the mc0011.jpg is blank

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I could've been able to solve it if it didn't had those extra stuffs at the end

mckenzieandjesus
 one year ago
Best ResponseYou've already chosen the best response.0I said it is blank thats the missing number

mckenzieandjesus
 one year ago
Best ResponseYou've already chosen the best response.0its y+ [blank]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0lol...ok let me see if I can do it

mckenzieandjesus
 one year ago
Best ResponseYou've already chosen the best response.0i figured it out 7

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Step by step solution : Step 1 : Raise c to the 1st power Exponentiation : Equation at the end of step 1 : (((y2)+15y)+56)((y+7)•((y+(m•c))jpg)) = 0 Step 2 : Raise y to the 2nd power Exponentiation : Equation at the end of step 2 : ((y2 + 15y) + 56)  (y + 7) • (y + mc  jpg) = 0 Step 3 : Simplify y2+15y+56  (y+7)•(y+mcjpg) 3.1 Factor ymc+yjpg+8y7mc+7jpg+56 Try to factor this 6term polynomial into (2term) • (3term) Begin by splitting the 6term into two 3term polynomials: ymc+yjpg+8y and 7mc+7jpg+56 Next simplify each 3term polynomial by pulling out like terms: y • (mcjpg8) and 7 • (mcjpg8) Note that the two simplified polynomials have mcjpg8 in common Now adding the two simplified polynomials we get (7y) • (mcjpg8) Which is the desired factorization. Equation at the end of step 3 : (y  7) • (mc  jpg  8) = 0 Step 4 : Solve (y7)•(mcjpg8) = 0 Theory  Roots of a product : 4.1 A product of several terms equals zero. When a product of two or more terms equals zero, then at least one of the terms must be zero. We shall now solve each term = 0 separately In other words, we are going to solve as many equations as there are terms in the product Any solution of term = 0 solves product = 0 as well. Solving a Single Variable Equation : 4.2 Solve : y7 = 0 Add 7 to both sides of the equation : y = 7 Multiply both sides of the equation by (1) : y = 7 Solving a Single Variable Equation : 4.3 Solve mcjpg8 = 0 In this type of equations, having more than one variable (unknown), you have to specify for which variable you want the equation solved. We shall not handle this type of equations at this time. One solution was found : y = 7

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0please tell me I didn't just embarrassed myself in a public thing...but I hope i'm right
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