## mckenzieandjesus one year ago Identify the axis of symmetry and vertex of f(x) = –x2 –2x–1. Axis of symmetry: x = 1; Vertex: (– 1, –1) Axis of symmetry: x = 1; Vertex: (1, 0) Axis of symmetry: x = – 1; Vertex: ( 1, 0) Axis of symmetry: x = – 1; Vertex: (– 1, 0)

1. mckenzieandjesus

@freckles @welshfella

2. anonymous

@mckenzieandjesus you still here?

3. mckenzieandjesus

yes

4. welshfella

transform the function to vertex form which is a(x - b)^2 + c wher the vertex is (b,c) and the axis of symmetry is y = -b

5. Nnesha

or use the formula $\huge\rm \frac{ -b }{ 2a }$ to find x coordinate of the vertex then substitute x for its value into the original equation to find y-coordinate of the vertex and x coordinate of the vertex would be the axis of symmetry

6. mckenzieandjesus

what numbers would i put in that formula?

7. Nnesha

$\huge\rm Ax^2+Bx+C$ a= leading coefficient b-middle term c=constant

8. Nnesha