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mckenzieandjesus
 one year ago
Identify the axis of symmetry and vertex of f(x) = –x2 –2x–1.
Axis of symmetry: x = 1; Vertex: (– 1, –1)
Axis of symmetry: x = 1; Vertex: (1, 0)
Axis of symmetry: x = – 1; Vertex: ( 1, 0)
Axis of symmetry: x = – 1; Vertex: (– 1, 0)
mckenzieandjesus
 one year ago
Identify the axis of symmetry and vertex of f(x) = –x2 –2x–1. Axis of symmetry: x = 1; Vertex: (– 1, –1) Axis of symmetry: x = 1; Vertex: (1, 0) Axis of symmetry: x = – 1; Vertex: ( 1, 0) Axis of symmetry: x = – 1; Vertex: (– 1, 0)

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mckenzieandjesus
 one year ago
Best ResponseYou've already chosen the best response.0@freckles @welshfella

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@mckenzieandjesus you still here?

welshfella
 one year ago
Best ResponseYou've already chosen the best response.0transform the function to vertex form which is a(x  b)^2 + c wher the vertex is (b,c) and the axis of symmetry is y = b

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0`or` use the formula \[\huge\rm \frac{ b }{ 2a }\] to find x coordinate of the vertex then substitute x for its value into the original equation to find ycoordinate of the vertex and x coordinate of the vertex would be the axis of symmetry

mckenzieandjesus
 one year ago
Best ResponseYou've already chosen the best response.0what numbers would i put in that formula?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0\[\huge\rm Ax^2+Bx+C\] a= leading coefficient bmiddle term c=constant

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0please tag username we aren't getting notification :(
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