A ball is thrown into the air with an upward velocity of 36 ft/s. Its height h in feet after t seconds is given by the function mc016-1.jpg. In how many seconds does the ball reach its maximum height? Round to the nearest hundredth if necessary. What is the ball’s maximum height?
2.25 s; 10 ft
1.13 s; 32.5 ft
1.13 s; 30.25 ft
1.13 s; 70.75 ft

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the function is h=-16t^2+36t+10

@Mehek14

use the formula
\(\sf{\dfrac{-b}{2a}}\)

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