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carolinar7
 one year ago
log(2)6•log(6)8
carolinar7
 one year ago
log(2)6•log(6)8

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Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1is i log(6)2 •log(6)8 base 6 ??

carolinar7
 one year ago
Best ResponseYou've already chosen the best response.0No the first one is base two in the second one is base six

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1\[\huge\rm log_2 6 \times \log_6 8\] like this

carolinar7
 one year ago
Best ResponseYou've already chosen the best response.0How do you solve it

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1alright familiar the the change of base formula ?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1huh anywys i have to go chage of base formula \[\huge\rm \log_\color{ReD}{b} \color{blue}{a} =\frac{ \log \color{blue }{a} }{ log\color{ReD}{ b} }\] write both log in fraction ^by using change of base formula

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1then rewrite 8 in terms of base 2

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1make sense ?? @carolinar7

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1i'll do the log(6)8 \[\huge\rm \log_\color{ReD}{6} \color{blue}{8} =\frac{ \log \color{blue }{8} }{ log\color{ReD}{ 6} }\] rewrite 8 in terms of base 2 2 times 2 times 2 = 8 you can write it as 2^3 \[\large\rm \log_\color{ReD}{6} \color{blue}{8} =\frac{ \log \color{blue }{2^3} }{ log\color{ReD}{ 6} }\] apply the power rule power rule \[\large\rm log_b x^y = y \log_b x\] write log(2) 6 in fraction by using change of base formula. that's it
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