## carolinar7 one year ago log(2)6•log(6)8

1. Nnesha

is i log(6)2 •log(6)8 base 6 ??

2. carolinar7

No the first one is base two in the second one is base six

3. Nnesha

$\huge\rm log_2 6 \times \log_6 8$ like this

4. carolinar7

*and

5. carolinar7

Yes you got it

6. carolinar7

How do you solve it

7. carolinar7

@Nnesha

8. carolinar7

@PhantomCrow

9. carolinar7

@Michele_Laino

10. Nnesha

alright familiar the the change of base formula ?

11. Nnesha

hey ??

12. Nnesha

huh anywys i have to go chage of base formula $\huge\rm \log_\color{ReD}{b} \color{blue}{a} =\frac{ \log \color{blue }{a} }{ log\color{ReD}{ b} }$ write both log in fraction ^by using change of base formula

13. Nnesha

then rewrite 8 in terms of base 2

14. Nnesha

make sense ?? @carolinar7

15. Nnesha

i'll do the log(6)8 $\huge\rm \log_\color{ReD}{6} \color{blue}{8} =\frac{ \log \color{blue }{8} }{ log\color{ReD}{ 6} }$ rewrite 8 in terms of base 2 2 times 2 times 2 = 8 you can write it as 2^3 $\large\rm \log_\color{ReD}{6} \color{blue}{8} =\frac{ \log \color{blue }{2^3} }{ log\color{ReD}{ 6} }$ apply the power rule power rule $\large\rm log_b x^y = y \log_b x$ write log(2) 6 in fraction by using change of base formula. that's it