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Elenathehomeschooler
 one year ago
Can someone help!
A handy man knows from experience that his 29foot ladder rests in its most stable position when the distance of its base from a wall is 1 foot farther than the height it reaches up the wall.
1. Draw a diagram to represent this situation. Be sure to label all unknown values in the problem.
2. Write an equation that you can use to find the unknown lengths in this situation. This equation should come directly from the labels you used in your diagram.
3. How far up a wall does this ladder reach? Show your work.
Elenathehomeschooler
 one year ago
Can someone help! A handy man knows from experience that his 29foot ladder rests in its most stable position when the distance of its base from a wall is 1 foot farther than the height it reaches up the wall. 1. Draw a diagram to represent this situation. Be sure to label all unknown values in the problem. 2. Write an equation that you can use to find the unknown lengths in this situation. This equation should come directly from the labels you used in your diagram. 3. How far up a wall does this ladder reach? Show your work.

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Vocaloid
 one year ago
Best ResponseYou've already chosen the best response.2dw:1444344809146:dw

Vocaloid
 one year ago
Best ResponseYou've already chosen the best response.2use the pythagorean theorem to find x

31356
 one year ago
Best ResponseYou've already chosen the best response.0Just a reminder, the Pythagorean theorem is a^2+b^2=c^2

Elenathehomeschooler
 one year ago
Best ResponseYou've already chosen the best response.0@31356 can you help me all i have so far is dw:1444345667230:dw im stuck

Elenathehomeschooler
 one year ago
Best ResponseYou've already chosen the best response.0@jim_thompson5910 can you help me

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.2dw:1444346208997:dw \[\Large a^2 + b^2 = c^2\] \[\Large x^2 + (x+1)^2 = 29^2\] \[\Large x^2 + \color{red}{(x+1)^2} = 841\] \[\Large x^2 + \color{red}{(x+1)(x+1)} = 841\] \[\Large x^2 + \color{red}{x^2+2x+1} = 841\] \[\Large 2x^2+2x+1 = 841\] Now get everything to one side and use the quadratic formula to find x

Elenathehomeschooler
 one year ago
Best ResponseYou've already chosen the best response.0so put dw:1444346934670:dw in thr quadratic formula @jim_thompson5910

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.2dw:1444347129681:dw

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.2dw:1444347161312:dw

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.2dw:1444347184674:dw

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.2dw:1444347206109:dw

Elenathehomeschooler
 one year ago
Best ResponseYou've already chosen the best response.0okay i got x=22.5 or x=76 did i get it right? @jim_thompson5910

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.2both are incorrect

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.22x^2 + 2x  840 = 0 a = 2 b = 2 c = 840 \[\Large x=\frac{b \pm \sqrt{b^24ac}}{2a}\] \[\Large x=\frac{2 \pm \sqrt{2^24*2*(840)}}{2*2}\] \[\Large x=\frac{2 \pm \sqrt{6724}}{4}\] \[\Large x=\frac{2 \pm 82}{4}\] \[\Large x=\frac{2 + 82}{4} \ \text{ or } \ x=\frac{2  82}{4}\] \[\Large x=\frac{80}{4} \ \text{ or } \ x=\frac{84}{4}\] \[\Large x=20 \ \text{ or } \ x=21\]

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.2go back to Vocaloid's drawing notice how x is a height or distance we can't have negative distance, so x = 21 makes no sense. The only practical answer is x = 20

Elenathehomeschooler
 one year ago
Best ResponseYou've already chosen the best response.0oh okay i noticed what i did wrong

Elenathehomeschooler
 one year ago
Best ResponseYou've already chosen the best response.0for number 3 the ladder will reach 29ft. on the wall right @jim_thompson5910

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.229 isn't the vertical distance 29 is the length of the ladder

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.2again, look back at Vocaloid's drawing
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