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dinorap1
 one year ago
Help me out with this linear programming problem please! I will post the question as a screenshot below!
dinorap1
 one year ago
Help me out with this linear programming problem please! I will post the question as a screenshot below!

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dinorap1
 one year ago
Best ResponseYou've already chosen the best response.1This is the question I need help with. Please help!

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.3`The production of y can exceed x by no more than 200` translates to what inequality?

dinorap1
 one year ago
Best ResponseYou've already chosen the best response.1That's what's stumping me here... I'm not sure how to write that one out.

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.3it would translate to `y <= x+200` basically `x+200` is the ceiling or max value for y. It can't go any higher

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.3also, it's implicitly stated that `x >= 0` and `y >= 0` since x and y are the number of products made

dinorap1
 one year ago
Best ResponseYou've already chosen the best response.1Oh okay. So now all I have to do is write it out on a graph and plug the vertices into the equation?

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.3so what you need to do is graph this system of inequalities \[\Large \begin{cases}y \le x+200\\ x+2y \le 1600\\ x \ge 0\\ y \ge 0\end{cases}\]

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.3find the shaded feasible region and the corner points of that region. Then plug each corner point into the profit function

dinorap1
 one year ago
Best ResponseYou've already chosen the best response.1Oh wow, thanks for writing it like that! That helps a lot! :D I have a graphing tool that does it for me. Maybe you can look at it after I'm done to see if I'm doing it right...

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.3sure I can do that

dinorap1
 one year ago
Best ResponseYou've already chosen the best response.1Alright I'm almost done graphing it...

dinorap1
 one year ago
Best ResponseYou've already chosen the best response.1Here's what it looks like...

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.3don't forget x >= 0 and y >= 0 when you graph all 4 inequalities and focus on the region where all shaded regions overlap, you'll get this

dinorap1
 one year ago
Best ResponseYou've already chosen the best response.1So my graph doesn't look right yet...?

dinorap1
 one year ago
Best ResponseYou've already chosen the best response.1Now it looks like this. :/

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.3it's a mess when you do all 4 graphs at the same time https://www.desmos.com/calculator/wpwycrhycx but with the link above, you can turn on/off graphs so you can see them individually or grouped

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.3yeah that looks better. if you focus on the region where all 4 graphs have in common, you'll have this region here

dinorap1
 one year ago
Best ResponseYou've already chosen the best response.1That looks much better than my graph. I still know the general area where all the vertices are, so I can probably deal with it looking messy like this... is my graph still accurate besides that?

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.3each corner point is found by finding the intersection of the lines

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.3example: (0,200) is found by finding the intersection of the lines `x = 0` and `y=x+200`

dinorap1
 one year ago
Best ResponseYou've already chosen the best response.1I'm getting a little confused... x>=0 isn't a line, is it? It just prevents x from equalling 0 I thought...

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.3`x = 0` is the boundary line to `x >= 0`

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.3`x = 0` is the y axis `x >= 0` means you shade to the right of the y axis

dinorap1
 one year ago
Best ResponseYou've already chosen the best response.1Okay I think the answer is C, which is: (1600,0) Is that right?

dinorap1
 one year ago
Best ResponseYou've already chosen the best response.1I need to go really soon

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.3yep the profit is P = 21500 at (x,y) = (1600,0) which is the max profit

dinorap1
 one year ago
Best ResponseYou've already chosen the best response.1Okay I'm about to submit it then... hope I don't get a crappy grade! I've been working on this for hours!

dinorap1
 one year ago
Best ResponseYou've already chosen the best response.1I got a 3/3! Thank you for helping! You really helped me understand this better! :)
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