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anonymous
 one year ago
The position of an object at time t is given by s(t) = 9  5t. Find the instantaneous velocity at t = 4 by finding the derivative.
anonymous
 one year ago
The position of an object at time t is given by s(t) = 9  5t. Find the instantaneous velocity at t = 4 by finding the derivative.

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IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.0\[{ds(t) \over dt} = v(t) = { d\over dt}(9  5t)\] \[{d \over dt} (9) = ??\] \[{d \over dt} (5t) = ??\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0what? sorry that is confusing me

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.0ok you are asked to find the derivative of: \(s(t) = 9  5t\) that will give you an equation for the velocity \(v(t)\) of the object. how do you propose to do that?

wmj259
 one year ago
Best ResponseYou've already chosen the best response.0That is correct. The velocity is the derivative of the position function.

wmj259
 one year ago
Best ResponseYou've already chosen the best response.0If you plug in a specific time into the velocity function you find the INSTANTANEOUS SPEED.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So if i put v (9) = ds/d(9)

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.0i strongly suggest you do the derivative first. then you will see :p

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Yeah see the problem is I dont know how to do any of this, like for this lesson i missed it in school, and im doing a review right now for the quiz tomorrow and i dont understand this at all

wmj259
 one year ago
Best ResponseYou've already chosen the best response.0@IrishBoy123, Yes that would make your night much easier. By taking the derivative of the position function you get the velocity function. But in this case its not much of a velocity FUNCTION then it is a velocity CONSTANT.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0sO IT WOULD BE a velocity constant? whats that

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@Loser66 @satellite73

wmj259
 one year ago
Best ResponseYou've already chosen the best response.0Yes, But if you take the derivative of the position function, what do you get?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0idk? how would i find that
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