MTALHAHASSAN2
  • MTALHAHASSAN2
Differentiate each of the following function: y=3/(3-x^2)^2
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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MTALHAHASSAN2
  • MTALHAHASSAN2
do we have to used the quotient rule??
Bossvideogamer21
  • Bossvideogamer21
what is the quotient rule?
Bossvideogamer21
  • Bossvideogamer21
@MTALHAHASSAN2 ?

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More answers

anonymous
  • anonymous
no don't use it if the numerator is a constant
anonymous
  • anonymous
think of it as \[y=3(3-x^2)^{-2}\] and use the power and chain rule
MTALHAHASSAN2
  • MTALHAHASSAN2
wait what you mean that the numerator is a constant
MTALHAHASSAN2
  • MTALHAHASSAN2
@satellite73
MTALHAHASSAN2
  • MTALHAHASSAN2
|dw:1444352168711:dw|
MTALHAHASSAN2
  • MTALHAHASSAN2
then is it be like that
anonymous
  • anonymous
i mean if the numerator is a number has no variable in it
anonymous
  • anonymous
and no, that answer is wrong @Jhannybean will help
Jhannybean
  • Jhannybean
\[\large y=\frac{3}{(3-x^2)^2} \qquad \implies \qquad y=3(3-x^2)^{-2}\]\[\begin{align} y' &= (3\cdot (-2)) \cdot (3-x^2)^{-2-1} \cdot \frac{d}{dx} (3-x^2) \\&=-6(3-x^2)^{-3} \cdot -2x \\&= -12x(3-x^2)^{-3} \\ \ &= \boxed{-\frac{12x}{(3-x^2)^3}}\end{align}\]
MTALHAHASSAN2
  • MTALHAHASSAN2
@Jhannybean In my answer at the back of the book they don't have a negative but otherwise its all look good
Jhannybean
  • Jhannybean
What does the back of the book say?
MTALHAHASSAN2
  • MTALHAHASSAN2
they have to same answer as your but you have a negative sign in front of -12x
MTALHAHASSAN2
  • MTALHAHASSAN2
the
MTALHAHASSAN2
  • MTALHAHASSAN2
|dw:1444355117207:dw|
MTALHAHASSAN2
  • MTALHAHASSAN2
@Jhannybean why don't you do it like this
Jhannybean
  • Jhannybean
i cant read all of your work and it looks a little confusing.,
MTALHAHASSAN2
  • MTALHAHASSAN2
Ok so I wrote was Y1=3(3-x^2)^-2 + 3(3-x^2)(-2x)
MTALHAHASSAN2
  • MTALHAHASSAN2
@jhannybean
anonymous
  • anonymous
-6*-2=12
MTALHAHASSAN2
  • MTALHAHASSAN2
What??
anonymous
  • anonymous
Jhannybean is correct only -6*-2x=12x
MTALHAHASSAN2
  • MTALHAHASSAN2
Wait which processes Is she using
anonymous
  • anonymous
Jhannybean you have mentioned -6*-2x=-12x which should be 12x
MTALHAHASSAN2
  • MTALHAHASSAN2
WHY DON'T SHE PUT 3 IN THE RIGHT SIDE
MTALHAHASSAN2
  • MTALHAHASSAN2
@surjithayer
anonymous
  • anonymous
you can put in the right hand side but\[\frac{ d }{ dx }\left( af \left( x \right) \right)=a \frac{ d }{ dx }\left( f \left( x \right) \right)\] where a is a constant but it is good if you put in front.
MTALHAHASSAN2
  • MTALHAHASSAN2
You mean 3 is constant so that's it be 0

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