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MTALHAHASSAN2

  • one year ago

Differentiate each of the following function: y=3/(3-x^2)^2

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  1. MTALHAHASSAN2
    • one year ago
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    do we have to used the quotient rule??

  2. Bossvideogamer21
    • one year ago
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    what is the quotient rule?

  3. Bossvideogamer21
    • one year ago
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    @MTALHAHASSAN2 ?

  4. anonymous
    • one year ago
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    no don't use it if the numerator is a constant

  5. anonymous
    • one year ago
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    think of it as \[y=3(3-x^2)^{-2}\] and use the power and chain rule

  6. MTALHAHASSAN2
    • one year ago
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    wait what you mean that the numerator is a constant

  7. MTALHAHASSAN2
    • one year ago
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    @satellite73

  8. MTALHAHASSAN2
    • one year ago
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    |dw:1444352168711:dw|

  9. MTALHAHASSAN2
    • one year ago
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    then is it be like that

  10. anonymous
    • one year ago
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    i mean if the numerator is a number has no variable in it

  11. anonymous
    • one year ago
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    and no, that answer is wrong @Jhannybean will help

  12. Jhannybean
    • one year ago
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    \[\large y=\frac{3}{(3-x^2)^2} \qquad \implies \qquad y=3(3-x^2)^{-2}\]\[\begin{align} y' &= (3\cdot (-2)) \cdot (3-x^2)^{-2-1} \cdot \frac{d}{dx} (3-x^2) \\&=-6(3-x^2)^{-3} \cdot -2x \\&= -12x(3-x^2)^{-3} \\ \ &= \boxed{-\frac{12x}{(3-x^2)^3}}\end{align}\]

  13. MTALHAHASSAN2
    • one year ago
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    @Jhannybean In my answer at the back of the book they don't have a negative but otherwise its all look good

  14. Jhannybean
    • one year ago
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    What does the back of the book say?

  15. MTALHAHASSAN2
    • one year ago
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    they have to same answer as your but you have a negative sign in front of -12x

  16. MTALHAHASSAN2
    • one year ago
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    the

  17. MTALHAHASSAN2
    • one year ago
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    |dw:1444355117207:dw|

  18. MTALHAHASSAN2
    • one year ago
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    @Jhannybean why don't you do it like this

  19. Jhannybean
    • one year ago
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    i cant read all of your work and it looks a little confusing.,

  20. MTALHAHASSAN2
    • one year ago
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    Ok so I wrote was Y1=3(3-x^2)^-2 + 3(3-x^2)(-2x)

  21. MTALHAHASSAN2
    • one year ago
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    @jhannybean

  22. anonymous
    • one year ago
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    -6*-2=12

  23. MTALHAHASSAN2
    • one year ago
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    What??

  24. anonymous
    • one year ago
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    Jhannybean is correct only -6*-2x=12x

  25. MTALHAHASSAN2
    • one year ago
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    Wait which processes Is she using

  26. anonymous
    • one year ago
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    Jhannybean you have mentioned -6*-2x=-12x which should be 12x

  27. MTALHAHASSAN2
    • one year ago
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    WHY DON'T SHE PUT 3 IN THE RIGHT SIDE

  28. MTALHAHASSAN2
    • one year ago
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    @surjithayer

  29. anonymous
    • one year ago
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    you can put in the right hand side but\[\frac{ d }{ dx }\left( af \left( x \right) \right)=a \frac{ d }{ dx }\left( f \left( x \right) \right)\] where a is a constant but it is good if you put in front.

  30. MTALHAHASSAN2
    • one year ago
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    You mean 3 is constant so that's it be 0

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