owlet
  • owlet
Enthalpy I need step-by-step guidance please and thank you in advance. Question Below:
Chemistry
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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owlet
  • owlet
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owlet
  • owlet
@Jhannybean
Jhannybean
  • Jhannybean
\[\Delta H = \sum {n\cdot \text{products} -\sum m \cdot \text{reactants}}\] m and n are coefficients of the reactants and products,respectively.

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Jhannybean
  • Jhannybean
So you're given \(\Delta H = -89 \frac{kJ}{mol}\)
owlet
  • owlet
yeah i think I manage it now, just to make sure Hf for I2 is zero right?
owlet
  • owlet
**can
Jhannybean
  • Jhannybean
Yes, all diatomics and elements
owlet
  • owlet
thanks!
Jhannybean
  • Jhannybean
\[-89 \frac{kJ}{mol} = -840\frac{kJ}{mol} +2\text{IF} -\left( -942 \frac{kJ}{mol}\right)\]
owlet
  • owlet
that's what i did and i got -94.5 kJ
Jhannybean
  • Jhannybean
- 89 = 2x - 840 + 942 -89 = 2x +102 -89 - 102 = 2x -191 = 2x x = -191/2 = -95.5

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