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owlet
 one year ago
Enthalpy
I need stepbystep guidance please and thank you in advance.
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owlet
 one year ago
Enthalpy I need stepbystep guidance please and thank you in advance. Question Below:

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\Delta H = \sum {n\cdot \text{products} \sum m \cdot \text{reactants}}\] m and n are coefficients of the reactants and products,respectively.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So you're given \(\Delta H = 89 \frac{kJ}{mol}\)

owlet
 one year ago
Best ResponseYou've already chosen the best response.0yeah i think I manage it now, just to make sure Hf for I2 is zero right?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Yes, all diatomics and elements

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[89 \frac{kJ}{mol} = 840\frac{kJ}{mol} +2\text{IF} \left( 942 \frac{kJ}{mol}\right)\]

owlet
 one year ago
Best ResponseYou've already chosen the best response.0that's what i did and i got 94.5 kJ

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0 89 = 2x  840 + 942 89 = 2x +102 89  102 = 2x 191 = 2x x = 191/2 = 95.5
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