anonymous
  • anonymous
ALGEBRA 2 HELP! Will fan and medal! http://prntscr.com/8pb5vg
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
is it clear that you are supposed to put \(-3\) where you see the \(x\)?
anonymous
  • anonymous
i.e compute \[f(-3)=|2\times (-3)-1|-5\]
anonymous
  • anonymous
so which is the answer? @u@ i'm still confused

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
@satellite73
anonymous
  • anonymous
did you compute the number? that is what you need to do
anonymous
  • anonymous
what is \(2\times (-3)\)?
anonymous
  • anonymous
-6
anonymous
  • anonymous
ok so we have \[|2\times (-3)-1|-5=|-6-1|-5\]
anonymous
  • anonymous
what is \(-6-1\)?
anonymous
  • anonymous
-7?
anonymous
  • anonymous
yes now we are at \[|-7|-5\] so what is \(|-7|\)?
anonymous
  • anonymous
7.
anonymous
  • anonymous
So is that the answer?
anonymous
  • anonymous
Cos it can't be. The choices are 2, -12, 0, and -10.
anonymous
  • anonymous
@satellite73

Looking for something else?

Not the answer you are looking for? Search for more explanations.