anonymous
  • anonymous
HELP WILL GIVE MEDAL ALGEBRA 2
Mathematics
  • Stacey Warren - Expert brainly.com
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
chestercat
  • chestercat
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Defiance
  • Defiance
Hello stanger!
anonymous
  • anonymous
\[(3\div \sqrt{75})-5\]
anonymous
  • anonymous
plz help :D

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Defiance
  • Defiance
First find 75 squared
Jhannybean
  • Jhannybean
\[\frac{3}{\sqrt{75}} -5\]
anonymous
  • anonymous
I MESSED UP 75 should be 11!!!
Defiance
  • Defiance
square root*
anonymous
  • anonymous
lol my bad
Defiance
  • Defiance
Okay.
Jhannybean
  • Jhannybean
\[\frac{3}{\sqrt{11}}-5\] is this your problem?
anonymous
  • anonymous
yes
Jhannybean
  • Jhannybean
\[\frac{3}{\sqrt{11}} - \frac{5}{1}\] what is the LCD between \(\sqrt{11}\) and 5?
Jhannybean
  • Jhannybean
sorry,\(\sqrt{11}\) and \(1\) **
anonymous
  • anonymous
1? :/
Jhannybean
  • Jhannybean
Not quite, it'd be the multiplication of both of these, \(\sqrt{11} \cdot 1 = \sqrt{11}\)
anonymous
  • anonymous
and then what?
Jhannybean
  • Jhannybean
Now we need a common denominator of \(\sqrt{11}\) for both fractions so we need to multiply the numerator and denominator of \(\dfrac{5}{1}\) by \(\sqrt{11}\)
Jhannybean
  • Jhannybean
Then we get \[\frac{3}{\sqrt{11}} - \frac{5\sqrt{11}}{\sqrt{11}} = \frac{3-5\sqrt{11}}{\sqrt{11}}\]
Jhannybean
  • Jhannybean
Not exactly sure what you were looking for though, hmm..
anonymous
  • anonymous
thanks for trying to help. idek :(

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