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anonymous

  • one year ago

HELP WILL GIVE MEDAL ALGEBRA 2

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  1. Defiance
    • one year ago
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    Hello stanger!

  2. anonymous
    • one year ago
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    \[(3\div \sqrt{75})-5\]

  3. anonymous
    • one year ago
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    plz help :D

  4. Defiance
    • one year ago
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    First find 75 squared

  5. Jhannybean
    • one year ago
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    \[\frac{3}{\sqrt{75}} -5\]

  6. anonymous
    • one year ago
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    I MESSED UP 75 should be 11!!!

  7. Defiance
    • one year ago
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    square root*

  8. anonymous
    • one year ago
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    lol my bad

  9. Defiance
    • one year ago
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    Okay.

  10. Jhannybean
    • one year ago
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    \[\frac{3}{\sqrt{11}}-5\] is this your problem?

  11. anonymous
    • one year ago
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    yes

  12. Jhannybean
    • one year ago
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    \[\frac{3}{\sqrt{11}} - \frac{5}{1}\] what is the LCD between \(\sqrt{11}\) and 5?

  13. Jhannybean
    • one year ago
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    sorry,\(\sqrt{11}\) and \(1\) **

  14. anonymous
    • one year ago
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    1? :/

  15. Jhannybean
    • one year ago
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    Not quite, it'd be the multiplication of both of these, \(\sqrt{11} \cdot 1 = \sqrt{11}\)

  16. anonymous
    • one year ago
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    and then what?

  17. Jhannybean
    • one year ago
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    Now we need a common denominator of \(\sqrt{11}\) for both fractions so we need to multiply the numerator and denominator of \(\dfrac{5}{1}\) by \(\sqrt{11}\)

  18. Jhannybean
    • one year ago
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    Then we get \[\frac{3}{\sqrt{11}} - \frac{5\sqrt{11}}{\sqrt{11}} = \frac{3-5\sqrt{11}}{\sqrt{11}}\]

  19. Jhannybean
    • one year ago
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    Not exactly sure what you were looking for though, hmm..

  20. anonymous
    • one year ago
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    thanks for trying to help. idek :(

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