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anonymous

  • one year ago

PROJECTILE MOTION A cannon shoots horizontally off a 90 m high cliff with a speed of 90 m/s. How much time until the cannonball hits the ground?

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  1. matt101
    • one year ago
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    All you're interested in is stuff going on in the vertical direction. This means its horizontal speed doesn't affect your answer. So what do we know? Starting vertical speed, v0 = 0 m/s (cannonball starts from rest) Vertical acceleration, a = 9.8 m/s^2 (gravity) Vertical distance, d = 90 m (height of the cliff) We want to find time, t. What equation can we use to solve for t using the variables we already have?

  2. anonymous
    • one year ago
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    \( \color {maroon}{\text {This}~\text {is} ~ \text {what}~ \text {I've}~\text{done}\text{:}}\)\[\Delta_y=V_yt+\frac{1}{2}at^2\]\[-90=-4.9t^2\]\[t=4.29 s\] @matt101

  3. matt101
    • one year ago
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    Looks good!

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