• anonymous
I need to write a net ionic equation to the following question. I have the answer below the question. How many grams of NaCl are required to precipitate most of the Ag+ ions from 2.50 × 102 mL of 0.0113 M AgNO3 solution? Write the net ionic equation for the reaction. AgNO3 moles = .0113x.250= .002825= 2.825x10-3 AgNO3=NaCl NaCl grams = 2.825x10-3x58= .1638≈.164g
Chemistry
• Stacey Warren - Expert brainly.com
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SOLVED
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