anonymous
  • anonymous
Will fan & medal Simplify: 2 (^3sqrt108)
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
@dan815 @zepdrix @Directrix
Directrix
  • Directrix
Is this supposed to be: 2 ^ (3sqrt108) ? Two raised to the (3 times square root of 108) power?
anonymous
  • anonymous
No, its just the number 2 being multiplied by the sqrt of 108 that has ^3 in front of the sqrt sign... I learned in my lesson that it means 108^1/3

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anonymous
  • anonymous
@Directrix
johnweldon1993
  • johnweldon1993
Oh okay \(\large 2(\sqrt[3]{108})\)
anonymous
  • anonymous
Yes!!
johnweldon1993
  • johnweldon1993
So try and think about cubed roots \(\large 2^3 = 8\) <---can this be evenly divided into 108? \(\large 3^3 = 27\) <---what about this? \(\large 4^3 = 64\) <--- or this? We know 64 cannot be evenly divided into 108..so ignore that...but in what way ...can we manipulate the numbers 3 and 2 to break down 108? *Remembering the key is cubed root*
anonymous
  • anonymous
Hmmm... I'm thrown off by the 3 and 2 you gave me to work with.. Not really sure what I'm supposed to do :/
johnweldon1993
  • johnweldon1993
Well the reason why I'm giving you that is because if you think about it \[\large \sqrt[3]{x^3} = x\] right? the 3 and the 3 cancel leaving just 'x'...so if we can find something that is raised to the third power....this can be simplified greatly So hint* (kinda a big one lol) \(\large 3^3 * 4\) what does that equal?
anonymous
  • anonymous
27 times 4 is 108 ;p
anonymous
  • anonymous
Wait!!
anonymous
  • anonymous
You may be reading too much into this because the goal is not to cancel out that exponent.. It still remains in the answer
johnweldon1993
  • johnweldon1993
Exactly :P So if we take your original question \[\large 2(\sqrt[3]{108})\] and write it as \(\large 2\sqrt[3]{(3^3 * 4)}\) that is the same ***and the exponent will still be in the answer btw :P *** just a way of breaking it down
anonymous
  • anonymous
My answer choices are: 16 3^sqrt18 8 3^sqrt6 5 3^sqrt4 6 3^sqrt4
anonymous
  • anonymous
Ohh okay haha got it
johnweldon1993
  • johnweldon1993
mmhmm i see the one i'm aiming at ;P
anonymous
  • anonymous
Lol!!!
johnweldon1993
  • johnweldon1993
Okay SO remember how i said \[\large \sqrt[3]{x^3} = x\] Well...lookey what we have here... \[\large 2(\sqrt[\color \red{3}]{\color \red{3^3} * 4})\]
anonymous
  • anonymous
oh!!! i know the answer now ;p
johnweldon1993
  • johnweldon1993
So now if we re-write this as \[\large 2(3\sqrt[3]{4})\] I believe you can do the rest ;P
anonymous
  • anonymous
so its 6 3^sqrt4
johnweldon1993
  • johnweldon1993
BAM! lol "ju got et chicha" ;p
anonymous
  • anonymous
Bahaha thanks bby ;*
johnweldon1993
  • johnweldon1993
Anytime puddin ;* lol

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