A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 one year ago
As soon as I think I've finished, more work appears! YAY! (EXTREME sarcasm). I'll give a medal to anyone who can help me with the problem I'm posting below. :)
anonymous
 one year ago
As soon as I think I've finished, more work appears! YAY! (EXTREME sarcasm). I'll give a medal to anyone who can help me with the problem I'm posting below. :)

This Question is Closed

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[(x^21)^\frac{5}{2} (x^3+5)\]

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1what are the instructions?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Sorry, the directions are to find the derivative. (not sure why i didn't post that?)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So far I've gotten...

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\:\left(x^21\right)^{\frac{5}{2}}\left(3x^2\right)+\left(x^3+5\right)\left(\frac{5}{2}\right)\left(x^21\right)^{\frac{3}{2}}\left(2x\right)\]

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1it looks great

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I'm not exactly sure what I should do next. Should I begin to simplify or is there another step involved?

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1there's not much to simplify after this point

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1the only thing I can see really is factoring but it's not much of a simplification if you ask me

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0My teacher prefers specifics unfortunately. Could you help me identify what parts should be factored?

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1notice there's a x^21 repeated

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1\[\large \left(x^21\right)^{\frac{5}{2}}\left(3x^2\right)+\left(x^3+5\right)\left(\frac{5}{2}\right)\left(x^21\right)^{\frac{3}{2}}\left(2x\right)\] \[\large \color{red}{\left(x^21\right)}^{\frac{5}{2}}\left(3x^2\right)+\left(x^3+5\right)\left(\frac{5}{2}\right)\color{red}{\left(x^21\right)}^{\frac{3}{2}}\left(2x\right)\]

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1Factor it out to get \[\large \color{red}{\left(x^21\right)}^{\frac{5}{2}}\left(3x^2\right)+\left(x^3+5\right)\left(\frac{5}{2}\right)\color{red}{\left(x^21\right)}^{\frac{3}{2}}\left(2x\right)\] \[\large \color{red}{\left(x^21\right)}^{\frac{3}{2}}\left(\left(x^21\right)\left(3x^2\right)+\left(x^3+5\right)\left(\frac{5}{2}\right)\left(2x\right)\right)\] as you can see, it's not much of a simplification

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1well now that I think about it more, the 5/2 and 2x multiply to 5x so that's something

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Question: How come the 3/2 exponent was kept but not the 5/2 ?

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1I factored out the portion with the 3/2 exponent

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1dw:1444358829913:dw

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1dw:1444358856055:dw

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1dw:1444358869946:dw

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1that's a similar example

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Okay, I think I understand. Is that the only factoring that can be done?

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1yeah I think so, but again, it's not much of a simplification

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1I guess you could do this \[\large \color{black}{\left(x^21\right)}^{\frac{3}{2}}\left(\left(x^21\right)\left(3x^2\right)+\left(x^3+5\right)\left(\frac{5}{2}\right)\left(2x\right)\right)\] \[\large \color{black}{\left(x^21\right)}^{\frac{3}{2}}\left((x^21)(3x^2)+(x^3+5)(5x)\right)\] \[\large \color{black}{\left(x^21\right)}^{\frac{3}{2}}\left(3x^33x^2+5x^4+25x\right)\] \[\large \color{black}{\left(x^21\right)}^{\frac{3}{2}}\left(35x^4+x^33x^2+25x\right)\]

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1sorry typo, let me fix

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1\[\large \color{black}{\left(x^21\right)}^{\frac{3}{2}}\left(\left(x^21\right)\left(3x^2\right)+\left(x^3+5\right)\left(\frac{5}{2}\right)\left(2x\right)\right)\] \[\large \color{black}{\left(x^21\right)}^{\frac{3}{2}}\left((x^21)(3x^2)+(x^3+5)(5x)\right)\] \[\large \color{black}{\left(x^21\right)}^{\frac{3}{2}}\left(3x^43x^2+5x^4+25x\right)\] \[\large \color{black}{\left(x^21\right)}^{\frac{3}{2}}\left(8x^43x^2+25x\right)\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Oh, that's perfect! Thank you yet again!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Now, I am off to learn about Extrema Derivatives. Wish me luck!
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.