anonymous
  • anonymous
When 0.422g of phosphorus is burned 0.967g of a white oxide is obtained. Determine the empirical formula of the oxide
Chemistry
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SOLVED
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jamiebookeater
  • jamiebookeater
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Shikamaru11
  • Shikamaru11
now what's that we gonna use the combustion analysis here too @Photon336 Sir???
Photon336
  • Photon336
@Shalante this is your type of problem.
Photon336
  • Photon336
i'm not sure myself @Shikamaru11 thoughts?

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More answers

Rushwr
  • Rushwr
Combustion is when u burn it in air soo we have to write the balanced equation for the reaction between phosphorus and O2
Shikamaru11
  • Shikamaru11
Sir will be the equation is something like that?????????? \[P+ZnO \rightarrow ????\] hope i could think far
Rushwr
  • Rushwr
Wait I dnt think we need to go for the equation. We can just assume that all of the phosphorus is now in the oxide.
Photon336
  • Photon336
\(\color{#0cbb34}{\text{Originally Posted by}}\) @Rushwr Combustion is when u burn it in air soo we have to write the balanced equation for the reaction between phosphorus and O2 \(\color{#0cbb34}{\text{End of Quote}}\) yeah, was thinking that too, BTW where did the zinc come from?
Rushwr
  • Rushwr
Considering phosphorus as the limiting agent
Shikamaru11
  • Shikamaru11
oh I got that in a second shot I think it mentioned white oxide but it's the obtant so my hypothesis failed :P
Shikamaru11
  • Shikamaru11
hey my guess of PO4 lolxxxx :P
Rushwr
  • Rushwr
we only need to find the empirical formula of the oxide right? So what if we consider that all of the phosphorus present are in the oxide now ? So the rest of the mass that is from 0.967 is oxygen SO the mass of oxygen in the oxide = 0.967 - 0.422 = 0.545g We can find the no. of moles of each separately Moles = mass/ molar mass moles of P = 0.422/ 31 = 0.014 moles Moles of Oxygen = 0.545/16 = 0.034 moles Now divide each by the smallest no. of moles |dw:1444362596720:dw| Now the ratio between P: O is 1:2.5 But we can't keep the ration in decimal numbers so to make it a whole number we multiply it by 2 so the new ratio would be 2:5 So the empirical formula would be P2O5
Rushwr
  • Rushwr
@Photon336 @Shikamaru11 What do u think Am i wrong somewhere?
Shikamaru11
  • Shikamaru11
hmmmm point to ponderwell you've won the world CUP :) friend @Rushwr
Rushwr
  • Rushwr
LOL ....... Thanks !!! @Shikamaru11
Shikamaru11
  • Shikamaru11
no dude you deserve it I'll call FIFA to give you the CUP next time :D :P :D
Rushwr
  • Rushwr
ROFL !!!!!!!!! Okai then I'll wait for it !!! >_< @Shikamaru11
Photon336
  • Photon336
omg now is a great time for a study group.
Rushwr
  • Rushwr
hahahahahaha Yaaaaaaaaaaaaasssssssssssss @Photon336
Photon336
  • Photon336
we've got Shalante you and shika
Rushwr
  • Rushwr
The only 2 missing here is Tara and woodward
Rushwr
  • Rushwr
Didn't hear from tara lately though
Rushwr
  • Rushwr
SO what are we up to ? Any questions before I leave.
Shikamaru11
  • Shikamaru11
:) i think that's enough for now my left eye got blanked and this chemistry :D but have you loved somebody :P @Rushwr
Rushwr
  • Rushwr
lol y? @Shikamaru11
Shikamaru11
  • Shikamaru11
you asked us to questio so i did :D @Rushwr
Rushwr
  • Rushwr
LOL I meant chemistry ones not this !!! @Shikamaru11
Shikamaru11
  • Shikamaru11
oh Sorry sir mistake Action replay :D :P @Rushwr :) stay happy
Rushwr
  • Rushwr
LOL I will I will @Shikamaru11
Rushwr
  • Rushwr
And not sir ! Miss
Shikamaru11
  • Shikamaru11
@Rushwr sorry ma'm I asked the wrong one I didn't know that you're ma'm :)
Rushwr
  • Rushwr
lol oki
Shikamaru11
  • Shikamaru11
@Rushwr thanks for being nice :)
Rushwr
  • Rushwr
No problem !!!! :) @Shikamaru11

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