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MTALHAHASSAN2
 one year ago
Differentiate each of the following function:
2x^31/x^2
MTALHAHASSAN2
 one year ago
Differentiate each of the following function: 2x^31/x^2

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MTALHAHASSAN2
 one year ago
Best ResponseYou've already chosen the best response.0F1(x)= 3(2x^21)(x^2)+(2x^31)(2x)

MTALHAHASSAN2
 one year ago
Best ResponseYou've already chosen the best response.0So the derivative of the given function be like that right

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.4well I'd start by writing both terms using index notation \[y = 2x^3  x^{2}\] now apply the rule for differentiation to both terms \[if~~ y = x^n ~~~y' = nx^{n  1}\]

MTALHAHASSAN2
 one year ago
Best ResponseYou've already chosen the best response.0Oh ok but you miss the 1

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.4no I didn't I used index notation \[\frac{1}{x^2} = x^{2}\]

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.4so is the question 1. \[y = 2x^3  \frac{1}{x^2}\] or 2. \[y = 2x^{3  \frac{1}{x^2}}\]

MTALHAHASSAN2
 one year ago
Best ResponseYou've already chosen the best response.0X^2 also a denominater of 2x^3

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.4ok... so its \[\frac{2x^3 1}{x^2}\]

MTALHAHASSAN2
 one year ago
Best ResponseYou've already chosen the best response.0F1(x)= 3(2x^21)(x^2)+(2x^31)(2x)

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.4ok so there are a couple of ways to do this... 1. use the quitient rule... or 2. split it into 2 fractions... \[y = \frac{2x^3}{x^2}  \frac{1}{x^2}\] so simplifying and using index notation you get \[y = 2x  x^{2}\] so the derivative is \[y' = 2 + \frac{2}{x^3}\]

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.4using the method you ahve attempted, which looks like the quotient rule you forgot the denominator if \[y = \frac{f(x)}{g(x)} \] then \[y' = \frac{g(x) f'(x)  f(x) g'(x)}{(g(x))^2}\]

MTALHAHASSAN2
 one year ago
Best ResponseYou've already chosen the best response.0No I guess that is product rule

MTALHAHASSAN2
 one year ago
Best ResponseYou've already chosen the best response.0Y′=f(x)1h(x)+f(x)h(x)1

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.4well if you are using the product rule you need to rewrite it using negative powers for the denominator \[\frac{2x^3 1}{x^2} = (2x^3 1)(x^{2})\] which will make a big difference

MTALHAHASSAN2
 one year ago
Best ResponseYou've already chosen the best response.0Oh ok but can I use any of them

MTALHAHASSAN2
 one year ago
Best ResponseYou've already chosen the best response.0I mean the rules

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.4you can use any of the rules, product rule, but careful with the power in the denominator quotient rule... normal diffierentiation rule after simplifying... they will all give the same answer

MTALHAHASSAN2
 one year ago
Best ResponseYou've already chosen the best response.0Wait then what is ur answer

MTALHAHASSAN2
 one year ago
Best ResponseYou've already chosen the best response.0F1(x)= 3(2x^21)(x)^2+(2x^31)2x

MTALHAHASSAN2
 one year ago
Best ResponseYou've already chosen the best response.0F1(x)=6x^2(x^21)4x(x^31)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0You're making it harder than it is

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[y=\frac{2x^31}{x^2} \iff y = (2x^31)(x^{2})\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[y'=2\cdot 3x^2 \cdot x^{2} + (2x^{3})(2x^31)\]\[y'=2\cdot 3x^{22} 2x^{3}(2x^3)+2x^{3}\]\[y'=6x^{0}(2\cdot 2)x^{0} +2x^{3}\]\[y'=64+2x^{3}\]\[y'= ...

triciaal
 one year ago
Best ResponseYou've already chosen the best response.0do you have any questions?

MTALHAHASSAN2
 one year ago
Best ResponseYou've already chosen the best response.0Can someone plz explain this question again to me??

triciaal
 one year ago
Best ResponseYou've already chosen the best response.0suggest you use parenthesis to make sure your question is clear

triciaal
 one year ago
Best ResponseYou've already chosen the best response.0dw:1444369433856:dw

MTALHAHASSAN2
 one year ago
Best ResponseYou've already chosen the best response.0I am having trouble after that positive sign.

triciaal
 one year ago
Best ResponseYou've already chosen the best response.03 approaches with practice you can decide which is better for you. end with the same answer.

MTALHAHASSAN2
 one year ago
Best ResponseYou've already chosen the best response.0I will go with easier one

triciaal
 one year ago
Best ResponseYou've already chosen the best response.01) the quotient rule 2)rewrite with index use product rule and chain rule 3) divide and do each term

MTALHAHASSAN2
 one year ago
Best ResponseYou've already chosen the best response.0Wait what you mean by the index

triciaal
 one year ago
Best ResponseYou've already chosen the best response.0that's the point they are all easy. with practice you will determine when to use which one or you can just stick to one format. personal preference.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I used the product rule: \(f' \cdot g + g' \cdot f\)

MTALHAHASSAN2
 one year ago
Best ResponseYou've already chosen the best response.0Can you please explain the second one

triciaal
 one year ago
Best ResponseYou've already chosen the best response.0what zepdrix did and also campbell above it's rewriting to use the product rule

MTALHAHASSAN2
 one year ago
Best ResponseYou've already chosen the best response.0I know the product one

triciaal
 one year ago
Best ResponseYou've already chosen the best response.0dw:1444370121922:dw

MTALHAHASSAN2
 one year ago
Best ResponseYou've already chosen the best response.0So lets us the product on e

triciaal
 one year ago
Best ResponseYou've already chosen the best response.0dw:1444370231542:dw

triciaal
 one year ago
Best ResponseYou've already chosen the best response.0dw:1444370312351:dw

triciaal
 one year ago
Best ResponseYou've already chosen the best response.0so you just need to know how to apply the rules and practice

triciaal
 one year ago
Best ResponseYou've already chosen the best response.0additional note you can use substitution to apply the chain rule

triciaal
 one year ago
Best ResponseYou've already chosen the best response.0any final questions on this?
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