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anonymous
 one year ago
can some one explain the concept of completing the square
will fan and medal
anonymous
 one year ago
can some one explain the concept of completing the square will fan and medal

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Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1alright \[\huge\rm Ax^2+Bx+C=0\] we should keep all the terms to the left side except the constant move the constant to the right side ( c is constant in this equation ) \[\large\rm ax^2+bx=c\] now we can complete the square at left side if there is a common factor(just the coefficient ) at left side take it out we need leading coefficient equal to one so i would divide both sides by a \[\rm x^2+\frac{bx}{a}=\frac{c}{a}\] \[\rm x^2+\frac{bx}{2a}=\frac{c}{a}\] now take `half` (b/2) of x term coefficient (middle term in the original equation bx) and the square it add( b/2)^2 both sides \[x^2+\frac{bx}{2a}+(\frac{b}{2a})^2 = \frac{c}{a}+(\frac{b}{2a})^2\]\[(x+\frac{b}{2a})^2= \frac{c}{a}+ (\frac{b}{2a})^2\] and then simplify like simple algebra you will get the quadratic formula

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1let's do an example \[\huge\rm x^2+6x+4=0\] `first move the constant to the right side` (subtract 4 both sides) \[\huge\rm x^2+6x=4\] take half of x term coefficient (which is 6 in this question ) and square it add square both sides of the equal sign (b/2)^2 \[x^2+ 6x +(\frac{ 6 }{ 2 })^2=4+(\frac{6}{2})^2\]

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1now simplify that 6/2 =3 \[\huge\rm x^2+6x+9=4+9\] \[(x+3)^2 =5 \] now to cancel out the square i willl square root \[\sqrt{(x+3)^2}=\sqrt{5} >x+3=\pm \sqrt{5}\] now we can move 3 to the right side \[x=3 \pm \sqrt{5}\]

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1make sense do you understand? sorry i have to go in few mints
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