find the distance from the line 4x+3y=5 to the point (6,9)

At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions.

A community for students.

find the distance from the line 4x+3y=5 to the point (6,9)

Mathematics
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions

distance equation?
m=-4/3 y-9=-4/3(x-6) y-9=-4/3x+8 y=-4/3x +17 (0, 5/3) and (6,9) d=s.rt (6-0)^2+(9-5/3)^2 =9.47511
perhaps try this.

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

The distance from a point P(x,o,yo) to a line ax+by+c = 0 is \[d=\frac{ \left| ax _{o}+by _{o}+c \right| }{ \sqrt{a^2+b^2} }\]
\[d=\frac{ \left| 4(6)+3(9)-5 \right| }{ \sqrt{4^2+3^2} }\]
been a while since I've done this so please correct me if i'm wrong
i got 9.2... but the hint say first find the line through the point (6,9) parallel to the given line, and then find the distance between these lines
you made a slight error on the slope of the line perpendicular to the given line its slope is - 1 / (-4/3) = 3/4
- oh the parallel line ! sorry
so was it right or wrong?
chrs00's method is correct and that comes to 9.2
yep
why did you use (0,5/3) on the original line?
i think he just used any point on that line. i think you need to use a point that is perpendicular to that line
distance=shortest distance
are u sure ..this question is structure different frm the previous set of questions that i did..they want .. to find distance frm the point (a,b) eg.(4,8) to the line y=sumthing eg 6x+8y=9 ... inwhich i used that formula provide by chrs00 but the question ask to find the distance frm the line given to the point given...
Chris00 formula gives you just that
you were given a point that did not lie on that line
another way to do it is to find the equation of the line perpendicular to the original line and passing through the point (6,9) then solving the 2 equations simultaneously to find the point of intersection. Then use the distance formula with this point and (6,9) But that's a bit long-winded.
ok
can u sketch it?
you can sketch it on the desmos web site
but i wouldnt get desmos to use in my test
the 2 parallel lines will look something like |dw:1444387746919:dw|
ok
the line joining the point (0, 5/3) and (6,9) is not perpendicular to the 2 parallel lines. That is why you didn't get the right answer
|dw:1444384572508:dw|
yea - did they give you that point (0. 5/3)?
no
i get that from the equation 4x+3y=5
yes i see Well you cant take any old point . The line joining the point to (6,9) must be perpendicular ( shortest distance)
ok
thank you both
: )
the formula that chris00 used is the easiest way to do it. Finding the line perpendicular etc ( the way i mentined) is long and messy yw
good luck in your studies

Not the answer you are looking for?

Search for more explanations.

Ask your own question