anonymous
  • anonymous
A helicopter flies at a constant altitude towing an airborne 100 kg crate as shown in the diagram. The helicopter and the crate only move in the horizontal direction and have an acceleration of 3.0 m/s2. Find the magnitude of the tension in the cable (in Newtons). Ignore the effects of air resistance.
Physics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
matt101
  • matt101
You didn't provide a diagram, but I'm assuming the cable is at an angle pointing away from the direction of motion. That means you can deconstruct the tension into horizontal and vertical components. The vertical component of the tension is the force of gravity on the crate, while the horizontal component of the tension is the forward force applied by the helicopter to produce the given acceleration: |dw:1444363914868:dw| You can now set up an equation based on the Pythagorean Theorem to solve for the tension: \[T^2=(mg)^2+(ma)^2\]\[T=\sqrt{m^2g^2+m^2a^2}\]\[T=m \sqrt{g^2+a^2}\]\[T=100 \sqrt{9.8^2+3^2}\]\[T=1025\] So the tension in the cable is about 1025 N! Does that make sense?

Looking for something else?

Not the answer you are looking for? Search for more explanations.