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anonymous
 one year ago
use the formula to evaluate the series
39+2781+...a8
anonymous
 one year ago
use the formula to evaluate the series 39+2781+...a8

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jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.0post the screenshot please

triciaal
 one year ago
Best ResponseYou've already chosen the best response.0there are 2 types of series arithmetic which has a common difference from one term to the next and the geometric progression that has a common ratio from on term to the next. can you now identify what kind of series this is?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i dont know how to do screen shot

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.0each term is found by multiplying the previous term by 3

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.03*(3) = 9 9*(3) = 27 27*(3) = 81 etc etc

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.0generate the first 8 terms, then add them up

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0okay hold on lets see

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.0alternatively, you can use this formula \[\Large S_n = a*\frac{1r^n}{1r}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yeah thats what its says to use

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.0yeah it's 4920

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0okay lets see ill send you a screen shot if its wrong okay

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.0ok I'm glad that one worked

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i have a question are you a teacher for algebra

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0because you seem to know what your doing

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.0yes I've had lots and lots of practice

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0sweet heres the other question

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.0this is a geometric series what's the first term? common ratio?

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.0first term = 1/3, yes

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0its going up in numerator x2 denomanator x3

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.0common ratio = 2/3

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.0r = 2/3 since r < 1 is true, this means the infinite series does converge and there is a fixed sum it reaches that sum would be S = a/(1r) S = (1/3)/(1(2/3)) S = (1/3)/(5/3) S = (1/3)*(3/5) S = 1/5

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.0Rule: if r < 1, then the series converges otherwise, the series diverges

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0okay so its fixed sum is 1/5

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.0if you generated all of the terms and added them up, they would add up to 1/5

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so converges are out right

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.0what do you mean? I wrote above that the series converges
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