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anonymous

  • one year ago

What is the equation, in standard form, of a parabola that models the values in the tables x: -2,0,4 f(x): 1,5,-59

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  1. triciaal
    • one year ago
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    |dw:1444365550534:dw|

  2. triciaal
    • one year ago
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    suggest substitute the values for (x,y) and solve the simultaneous equations to get a,b,c

  3. anonymous
    • one year ago
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    Can you explain how to do this

  4. triciaal
    • one year ago
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    substitute means replace now read my response again.

  5. anonymous
    • one year ago
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    I understand that but once i replace 1=a(-2)^2+b(-2)+c what do i do from there

  6. triciaal
    • one year ago
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    for each set

  7. triciaal
    • one year ago
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    do you know how to solve simultaneous equations? there are about 4 methods

  8. anonymous
    • one year ago
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    no i dont

  9. triciaal
    • one year ago
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    ok I will work with you what are the 3 equations?

  10. triciaal
    • one year ago
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    this is even simplier than i thought do you see C = 5?

  11. anonymous
    • one year ago
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    i guess

  12. triciaal
    • one year ago
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    no! if you have questions make sure you ask. it is very important for you to understand.

  13. triciaal
    • one year ago
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    what are the equations when you substitute the x and y values given?

  14. anonymous
    • one year ago
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    doesnt f(x) mean y?

  15. triciaal
    • one year ago
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    yes

  16. triciaal
    • one year ago
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    function of x

  17. anonymous
    • one year ago
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    so you make 3 equations and plug 1 x in for each?

  18. triciaal
    • one year ago
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    |dw:1444366987783:dw|

  19. triciaal
    • one year ago
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    y = f(x) = ax^2 + bx + c

  20. triciaal
    • one year ago
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    you did the first one correctly when x = -2 do the same process when x = 0 and again when x - 4

  21. anonymous
    • one year ago
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    ok so what do i do now that i have the 3 equations

  22. triciaal
    • one year ago
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    show what you have did you get C = 5?

  23. anonymous
    • one year ago
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    i dont understand how u got c=5

  24. triciaal
    • one year ago
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    did you do the substitutions?

  25. anonymous
    • one year ago
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    yes i got 5=a(0)^2+b(0)+c

  26. triciaal
    • one year ago
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    |dw:1444367515071:dw|

  27. triciaal
    • one year ago
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    remember zero times anything is zero

  28. triciaal
    • one year ago
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    show the 3rd one.

  29. anonymous
    • one year ago
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    -59=a(4)^2+b(4)+c

  30. triciaal
    • one year ago
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    and we can replace C with 5

  31. triciaal
    • one year ago
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    also for the first one C = 5

  32. triciaal
    • one year ago
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    |dw:1444367836458:dw|

  33. triciaal
    • one year ago
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    |dw:1444368031994:dw|

  34. anonymous
    • one year ago
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    what happened to -59?

  35. triciaal
    • one year ago
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    |dw:1444368144737:dw|

  36. triciaal
    • one year ago
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    |dw:1444368245388:dw|

  37. triciaal
    • one year ago
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    when you have an equation whatever you do to one side also do to the other to maintain the balance . always group like terms to simplify

  38. triciaal
    • one year ago
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    always factor when you can to use smaller numbers .

  39. triciaal
    • one year ago
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    by the way notice we had equations with 3 unknown we are using substitution to solve. we had the value for c and substituted in the others. we found the expressions for b and set them equal. this gave the linear equation (one unknown) and we solve for a.

  40. triciaal
    • one year ago
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    now that we have a,b and c we can write the general equation for f(x)

  41. triciaal
    • one year ago
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    please review and ask any questions if you need to clear anything up. I am short on time but you need to be able to do the problem on your own.

  42. anonymous
    • one year ago
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    i think i got it from here thank you

  43. triciaal
    • one year ago
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    yeah we are at the end you only have to write the equation.

  44. triciaal
    • one year ago
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    my question is do you clearly understand all what I did?

  45. anonymous
    • one year ago
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    Yes i do

  46. triciaal
    • one year ago
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    great!! review and keep practicing math is very easy with practice.

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