anonymous
  • anonymous
Can anyone help? The link is a picture of the problem. http://oi62.tinypic.com/2lbjmv9.jpg
Physics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
@matt101
BAdhi
  • BAdhi
during 2, there is a displacement of 15m for 0.5 hr velocity = displacement / time do the same for segment -3
anonymous
  • anonymous
So 30 m/s for v2 and 25 for v3?

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BAdhi
  • BAdhi
umm thats in km/h you have to convert it to m/s
anonymous
  • anonymous
3.0 x 10^3
anonymous
  • anonymous
v2=30 v3=3000? That doesn't make sense.
anonymous
  • anonymous
I'm pretty sure I'm not doing this right.
anonymous
  • anonymous
Sorry openstudy is messing up for me.
anonymous
  • anonymous
Hello?
BAdhi
  • BAdhi
you have to convert km -> m and also hrs -> seconds so 1km/h = 1000/3600 m/s
anonymous
  • anonymous
So it's v3=.277?
anonymous
  • anonymous
I'm getting confused could you work out the problem?
anonymous
  • anonymous
I'm confused and running short on time and I have another problem to work. Sorry.
matt101
  • matt101
Velocity is the change in position divided by the change in time. Change in anything is the final value minus the initial value of that thing So for interval #2, the change in position is 30 - 15 = 15 km, which is 15 000 m, and the change in time is 1.5 - 1 = 0.5 hours, which is 1800 seconds. The average velocity of interval #2 is therefore 15 000 / 1800 = 8.33 m/s Now you try the same process for #3!
anonymous
  • anonymous
I got 1.85 for #3
matt101
  • matt101
Looks good!

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