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anonymous

  • one year ago

Can anyone help? The link is a picture of the problem. http://oi62.tinypic.com/2lbjmv9.jpg

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  1. anonymous
    • one year ago
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    @matt101

  2. BAdhi
    • one year ago
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    during 2, there is a displacement of 15m for 0.5 hr velocity = displacement / time do the same for segment -3

  3. anonymous
    • one year ago
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    So 30 m/s for v2 and 25 for v3?

  4. BAdhi
    • one year ago
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    umm thats in km/h you have to convert it to m/s

  5. anonymous
    • one year ago
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    3.0 x 10^3

  6. anonymous
    • one year ago
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    v2=30 v3=3000? That doesn't make sense.

  7. anonymous
    • one year ago
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    I'm pretty sure I'm not doing this right.

  8. anonymous
    • one year ago
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    Sorry openstudy is messing up for me.

  9. anonymous
    • one year ago
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    Hello?

  10. BAdhi
    • one year ago
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    you have to convert km -> m and also hrs -> seconds so 1km/h = 1000/3600 m/s

  11. anonymous
    • one year ago
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    So it's v3=.277?

  12. anonymous
    • one year ago
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    I'm getting confused could you work out the problem?

  13. anonymous
    • one year ago
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    I'm confused and running short on time and I have another problem to work. Sorry.

  14. matt101
    • one year ago
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    Velocity is the change in position divided by the change in time. Change in anything is the final value minus the initial value of that thing So for interval #2, the change in position is 30 - 15 = 15 km, which is 15 000 m, and the change in time is 1.5 - 1 = 0.5 hours, which is 1800 seconds. The average velocity of interval #2 is therefore 15 000 / 1800 = 8.33 m/s Now you try the same process for #3!

  15. anonymous
    • one year ago
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    I got 1.85 for #3

  16. matt101
    • one year ago
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    Looks good!

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