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Can anyone help? The link is a picture of the problem. http://oi62.tinypic.com/2lbjmv9.jpg

Physics
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during 2, there is a displacement of 15m for 0.5 hr velocity = displacement / time do the same for segment -3
So 30 m/s for v2 and 25 for v3?

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umm thats in km/h you have to convert it to m/s
3.0 x 10^3
v2=30 v3=3000? That doesn't make sense.
I'm pretty sure I'm not doing this right.
Sorry openstudy is messing up for me.
Hello?
you have to convert km -> m and also hrs -> seconds so 1km/h = 1000/3600 m/s
So it's v3=.277?
I'm getting confused could you work out the problem?
I'm confused and running short on time and I have another problem to work. Sorry.
Velocity is the change in position divided by the change in time. Change in anything is the final value minus the initial value of that thing So for interval #2, the change in position is 30 - 15 = 15 km, which is 15 000 m, and the change in time is 1.5 - 1 = 0.5 hours, which is 1800 seconds. The average velocity of interval #2 is therefore 15 000 / 1800 = 8.33 m/s Now you try the same process for #3!
I got 1.85 for #3
Looks good!

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