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anonymous
 one year ago
Can anyone help? The link is a picture of the problem.
http://oi62.tinypic.com/2lbjmv9.jpg
anonymous
 one year ago
Can anyone help? The link is a picture of the problem. http://oi62.tinypic.com/2lbjmv9.jpg

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BAdhi
 one year ago
Best ResponseYou've already chosen the best response.0during 2, there is a displacement of 15m for 0.5 hr velocity = displacement / time do the same for segment 3

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So 30 m/s for v2 and 25 for v3?

BAdhi
 one year ago
Best ResponseYou've already chosen the best response.0umm thats in km/h you have to convert it to m/s

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0v2=30 v3=3000? That doesn't make sense.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I'm pretty sure I'm not doing this right.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Sorry openstudy is messing up for me.

BAdhi
 one year ago
Best ResponseYou've already chosen the best response.0you have to convert km > m and also hrs > seconds so 1km/h = 1000/3600 m/s

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I'm getting confused could you work out the problem?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I'm confused and running short on time and I have another problem to work. Sorry.

matt101
 one year ago
Best ResponseYou've already chosen the best response.1Velocity is the change in position divided by the change in time. Change in anything is the final value minus the initial value of that thing So for interval #2, the change in position is 30  15 = 15 km, which is 15 000 m, and the change in time is 1.5  1 = 0.5 hours, which is 1800 seconds. The average velocity of interval #2 is therefore 15 000 / 1800 = 8.33 m/s Now you try the same process for #3!
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