alli6106
  • alli6106
Find 3 consecutive odd intergers such that 8 times the first integer is 4 more than 20 times the third
Mathematics
jamiebookeater
  • jamiebookeater
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Directrix
  • Directrix
Let x be the first of the 3 consecutive odd numbers The second is x + 2 Third, x + 4 8 times the first integer 8x 20 times the third 20(x + 4) 4 more than 20 times the third 4 + 20(x+4)
Directrix
  • Directrix
8x = 20(x+4) + 4 8x = 20x + 80 + 4 @alli6106 Try your hand at solving for x.

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