anonymous
  • anonymous
Data downloaded from a permanent count station yielded that the evening peak hour traffic averaged 1915 (vph) and had a standard deviation of 430 (vph).  The data appear to follow a normal distribution. Previous analyses found that the roadway has a capacity of 2275 (vph).       a.) What is the probability that the hourly traffic will exceed capacity?
Mathematics
schrodinger
  • schrodinger
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this
and thousands of other questions

shaik0124
  • shaik0124
since the data is normal distribution median is 1915 ( avg is equal to median when data is equally spaced)
shaik0124
  • shaik0124
in normal distribution mean ,median and mode all are equal so the next hour traffic will be 1915+430 =2345
shaik0124
  • shaik0124
consider this set s={2,3,4,5} difference beween each number is 1 i.e,equally spaced now mean =(2+3+4+5)/4 =3.5 meadian =3+4)/2 =3.5

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

shaik0124
  • shaik0124
dou have answer choices to this question
anonymous
  • anonymous
No, but I think I got the answer.
shaik0124
  • shaik0124
so how did u solve
anonymous
  • anonymous
|dw:1444369978024:dw| So we want to probability that x > 2275. P(x>2275) z = x-u/o = 2275-1915/430 = 0.84 So now we have P(z>0.84) = 1-P(z<0.84) = 1- 0.7995 We get 0.7995 from something called the z score table. Here's a video with examples. https://www.youtube.com/watch?v=mai23vW8uFM

Looking for something else?

Not the answer you are looking for? Search for more explanations.