jojokiw3
  • jojokiw3
When graphing this equation, where do I put this part of it?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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jojokiw3
  • jojokiw3
\[y = 2+3 \sin [3(x-\frac{ \pi }{ 4 })]\] What do I do with the second 3?
anonymous
  • anonymous
@SoullessEyes
jojokiw3
  • jojokiw3
@zepdrix

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jojokiw3
  • jojokiw3
So 2 is the center line, 3 is the amplitude, pi/4 is the phase angle. What's the 3 in front of the x?
zepdrix
  • zepdrix
Sounds right so far! :) \[\large\rm y=A \sin[B(x-C)]+D\]A gives us amplitude, B gives us period in this way \(\rm Period=2\pi/B\), C is our phase shift, D moves the center line,
jojokiw3
  • jojokiw3
Oo, what's period?
zepdrix
  • zepdrix
It's the amount of time it takes for the sine function to complete one full cycle. Or in this case it would maybe be more appropriate to say, the amount of x for sine to complete a full cycle, to get back to it's starting point.
jojokiw3
  • jojokiw3
So is it like the "distance" from one high point to the next?
zepdrix
  • zepdrix
|dw:1444370686674:dw|
zepdrix
  • zepdrix
|dw:1444370742440:dw|A single period here
zepdrix
  • zepdrix
Yes, that's a good way to think of it!
zepdrix
  • zepdrix
Usually sine function starts at the mid point though, so measuring top to top might be a little weird
anonymous
  • anonymous
@zepdrix when done can u help me?
jojokiw3
  • jojokiw3
So for cosine it's maybe top to top, but sine it's mid to mid?
zepdrix
  • zepdrix
|dw:1444370812720:dw|This is one full period of the normal sine curve. So careful when you say mid to mid! :) We pass through the middle an extra time.
zepdrix
  • zepdrix
Notice that I've captured the entire shape with these red dots, One camel hump up, and one more down. Then it repeats that over and over.
jojokiw3
  • jojokiw3
Haha oh you're right. So basically two curves, though one of the cos curves is cut in half.
anonymous
  • anonymous
nvm its 11pm i gtg
zepdrix
  • zepdrix
ya cosine is a little weird. you're getting `half a camel hump`, then the entire lower one, then `another half of the upper one`.
jojokiw3
  • jojokiw3
I think I get it now. :D Thanks for explaining!
zepdrix
  • zepdrix
yay team \c:/

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