At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga.
Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus.
Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this and **thousands** of other questions.

I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this and **thousands** of other questions

Okay and so
\[\lambda=\frac{Q}{L}\] right? But is it the length of the whole cylinder?

you already did.. now integrate it from R1 (the radius of the wire) to R2 (radius of the pipe)

\[\lambda=\frac{ E }{ 2\pi \epsilon_0 }\ln(\frac{ R_2 }{ R_1 }) \]

Wait.. I overlooked.. why is there an E? :P
It should be lamda

I solved for lambda in the first equation you gave me and then integrated with respect to R >_< lol

Wait, I'm not actually sure what I did.. lol

I think I accidentally swapped the variables. It should be
E = lambda and the rest

yes.. just swap E and Lamda and you should be fine!

Sweet. And for the second part it's jsut F=qE? F=mg, so mg=qE and just solve for q?

Well 10mg since it says the F is 10 times the weight

10 times the weight

yea yea.. correct

you are all set on reducing pollution.. (Well theoretically :P)

ok shoot.. lets do one more before I go for lunch