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marigirl

  • one year ago

Having a blank moment.. please help me write square root of u on the top line

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  1. marigirl
    • one year ago
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    \[\frac{ 2u-1 }{ \sqrt{u} }\]

  2. marigirl
    • one year ago
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    does it become (2u-1)(u)^(-0.5)

  3. Compassionate
    • one year ago
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    Do you want o solve for u?

  4. marigirl
    • one year ago
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    i want to bring square root of u to the top

  5. marigirl
    • one year ago
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    \[\frac{ 2u-1 }{ \sqrt{u} }=2u-2*x ^{\frac{ -1 }{ 2 }}\]

  6. marigirl
    • one year ago
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    is that correct?

  7. marigirl
    • one year ago
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    i mean 2u-1

  8. Compassionate
    • one year ago
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    \[\frac{ (2u-1^{(0.05u)} }{ 1 }\]

  9. marigirl
    • one year ago
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    omg i cant do that....because its a relationship at the top!!!!!! opps

  10. anonymous
    • one year ago
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    (2u−1(0.05u)1

  11. marigirl
    • one year ago
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    \[\frac{ 2u-1 }{ \sqrt{u} }=\frac{ 2u }{ \sqrt{u} }-\frac{ 1 }{ \sqrt{u} }\]

  12. zepdrix
    • one year ago
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    If you multiply \(\rm \sqrt u\) by \(\rm \sqrt u\) will get rid of the square root down there :) ya?

  13. zepdrix
    • one year ago
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    \[\large\rm \frac{(2u-1)}{\sqrt{u}}\cdot\color{royalblue}{\frac{\sqrt u}{\sqrt u}}\]Gotta do this fancy business

  14. anonymous
    • one year ago
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    this is ok because your effectively multiplying by 1

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spraguer (Moderator)
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is replying to Can someone tell me what button the professor is hitting...

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