marigirl
  • marigirl
Having a blank moment.. please help me write square root of u on the top line
Mathematics
jamiebookeater
  • jamiebookeater
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marigirl
  • marigirl
\[\frac{ 2u-1 }{ \sqrt{u} }\]
marigirl
  • marigirl
does it become (2u-1)(u)^(-0.5)
Compassionate
  • Compassionate
Do you want o solve for u?

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marigirl
  • marigirl
i want to bring square root of u to the top
marigirl
  • marigirl
\[\frac{ 2u-1 }{ \sqrt{u} }=2u-2*x ^{\frac{ -1 }{ 2 }}\]
marigirl
  • marigirl
is that correct?
marigirl
  • marigirl
i mean 2u-1
Compassionate
  • Compassionate
\[\frac{ (2u-1^{(0.05u)} }{ 1 }\]
marigirl
  • marigirl
omg i cant do that....because its a relationship at the top!!!!!! opps
anonymous
  • anonymous
(2u−1(0.05u)1
marigirl
  • marigirl
\[\frac{ 2u-1 }{ \sqrt{u} }=\frac{ 2u }{ \sqrt{u} }-\frac{ 1 }{ \sqrt{u} }\]
zepdrix
  • zepdrix
If you multiply \(\rm \sqrt u\) by \(\rm \sqrt u\) will get rid of the square root down there :) ya?
zepdrix
  • zepdrix
\[\large\rm \frac{(2u-1)}{\sqrt{u}}\cdot\color{royalblue}{\frac{\sqrt u}{\sqrt u}}\]Gotta do this fancy business
anonymous
  • anonymous
this is ok because your effectively multiplying by 1

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