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Astrophysics
 one year ago
Could use a little help, relativity.
Astrophysics
 one year ago
Could use a little help, relativity.

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Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.0A rocket ship of proper length \(l_0\) travels at constant velocity \(v \) relative to a frame S. The nose of the ship \((A')\) passes the point \(A \) in S at \(t=t'=0\), and at this instant a light signal is sent from \(A'\) to \(B'\).

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.0Here's my figure dw:1444376673186:dw the time \[t' = \frac{ l_0 }{ c }\] for the sginal to reach the tail B' of the ship. My question is, at what time \(t_1\), as measured in S, does the signal reach the tail \(B'\) of the ship.

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.0dw:1444376950407:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0oh wait.. no sorry lolz

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.0Yeah, I sort of tried all of this already, I'm not quite sure at this point haha

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0But its still fairly simple all you need to do is contact the length and then use classical physics to figure out the time taken..

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.0\[\tau = \tau_0 \gamma\] I did try that oh..I think it's because this is the first question where I have the frames the other way around so my algebra must be wrong..

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.0\[l =\frac{ l_0 }{ \gamma }*\]

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.0Figured it out, thanks anyways @Mashy :)
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