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marigirl
 one year ago
could someone look over my integration by substitution steps?
marigirl
 one year ago
could someone look over my integration by substitution steps?

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marigirl
 one year ago
Best ResponseYou've already chosen the best response.1Question is to integrate \[\int\limits_{?}^{?} \frac{ 6x1 }{ \sqrt{3x+1} }\]

marigirl
 one year ago
Best ResponseYou've already chosen the best response.1i made u=3x+1 du/dx=3 so then dx=du/3

marigirl
 one year ago
Best ResponseYou've already chosen the best response.1u=3x+1 \[x=\frac{ u1 }{ 3 }\]

marigirl
 one year ago
Best ResponseYou've already chosen the best response.1Now I have \[\int\limits_{?}^{?} \frac{ 6(\frac{ u1 }{ 3 }) }{ \sqrt{u} } \times \frac{ du }{ 3 }\]

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1Now I have \[\int\limits_{?}^{?} \frac{ 6(\frac{ u1 }{ 3 })\color{red}{1} }{ \sqrt{u} } \times \frac{ du }{ 3 }\]

marigirl
 one year ago
Best ResponseYou've already chosen the best response.1then i did \[\frac{ 1 }{ 3 }\int\limits_{?}^{?}\frac{ 2u2 }{ \sqrt{u} }.du\]

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1then i did \[\frac{ 1 }{ 3 }\int\limits_{?}^{?}\frac{ 2u2 \color{red}{1}}{ \sqrt{u} }.du\]

marigirl
 one year ago
Best ResponseYou've already chosen the best response.1omg yes i forgot the plus one!!

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1omg yes i forgot the \(\color{Red}{minus}\) one!!

marigirl
 one year ago
Best ResponseYou've already chosen the best response.1pellet i miss typed it.. lol 6x+1 .. Sorry!!

marigirl
 one year ago
Best ResponseYou've already chosen the best response.1\[\int\limits_{?}^{?}\frac{ 6x+1 }{ \sqrt{3x+1} }\]

marigirl
 one year ago
Best ResponseYou've already chosen the best response.1so now we are at \[\frac{ 1 }{ 3 }\int\limits_{?}^{?}\frac{ 2u1 }{ \sqrt{u} }\]

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1looks good, keep going..

marigirl
 one year ago
Best ResponseYou've already chosen the best response.1then \[\frac{ 1 }{ 3 }\int\limits_{?}^{?} 2\sqrt{u} \times \frac{ 2 }{ \sqrt{u} }.du\]

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1do you mean \[\frac{ 1 }{ 3 }\int\limits_{?}^{?} 2\sqrt{u}  \frac{ 1 }{ \sqrt{u} }.du \]

marigirl
 one year ago
Best ResponseYou've already chosen the best response.1\[\frac{ 1 }{ 3 } \times \frac{ 4u ^{\frac{ 3 }{ 2 }} }{ 3 }+4u ^{\frac{ 1 }{ 2 }}\]

marigirl
 one year ago
Best ResponseYou've already chosen the best response.1oh gosh .....lol im a mess.. its a minus!

marigirl
 one year ago
Best ResponseYou've already chosen the best response.1so then i think finally i did \[\frac{ 4u ^{\frac{ 3 }{ 2 }} }{ 9 }\frac{ 4u ^{\frac{ 1 }{ 2 }} }{ 3 }\]

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1I think you should get \[\frac{ 1 }{ 3 } \left( \frac{ 4u ^{\frac{ 3 }{ 2 }} }{ 3 }2u ^{\frac{ 1 }{ 2 }}\right)\]

marigirl
 one year ago
Best ResponseYou've already chosen the best response.1yes cuz i did that error of not adding the plus one,..thanks so much! I really appreciate your time :D :D :D
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