mathmath333
  • mathmath333
Find the probablity that you get a total of more than 3 in a throw of 2 dice.
Mathematics
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mathmath333
  • mathmath333
Find the probablity that you get a total of more than 3 in a throw of 2 dice.
Mathematics
schrodinger
  • schrodinger
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mathmath333
  • mathmath333
\(\large \color{black}{\begin{align} & \normalsize \text{ Find the probablity that you get a total of more than }\hspace{.33em}\\~\\ & \normalsize \text{ 3 in a throw of 2 dice .}\hspace{.33em}\\~\\ \end{align}}\)
BAdhi
  • BAdhi
more than 3 -> 6x4 (1,2,3,4,5,6) and (3,4,5,6) all the possibilites -> 6x6 (1,2,3,4,5,6) and (1,2,3,4,5,6)
mathmath333
  • mathmath333
is it 24/36=2/3

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anonymous
  • anonymous
you could just do \[\Pr(T>3)=1-\Pr(T \le3)\]
anonymous
  • anonymous
would be less ways that way
anonymous
  • anonymous
and you know there are 36 combinations in total for rolling any number.
BAdhi
  • BAdhi
yes chris is correct.. btw i forgot about (3,1), (4,1),... (3,2), (4,2),... combinations I think its better to follow chris 's way
anonymous
  • anonymous
1,1 2,1 2,1 are the only combinations less than or equal to 3
mathmath333
  • mathmath333
is it 11/12
anonymous
  • anonymous
\[\Pr(X \le3)=\frac{ 1 }{ 36 }+\frac{ 2 }{ 36 }\]
anonymous
  • anonymous
ye
anonymous
  • anonymous
looks good
mathmath333
  • mathmath333
11/12 is correct
anonymous
  • anonymous
awesome

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