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mathmath333

  • one year ago

Find the probablity that you get a total of more than 3 in a throw of 2 dice.

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  1. mathmath333
    • one year ago
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    \(\large \color{black}{\begin{align} & \normalsize \text{ Find the probablity that you get a total of more than }\hspace{.33em}\\~\\ & \normalsize \text{ 3 in a throw of 2 dice .}\hspace{.33em}\\~\\ \end{align}}\)

  2. BAdhi
    • one year ago
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    more than 3 -> 6x4 (1,2,3,4,5,6) and (3,4,5,6) all the possibilites -> 6x6 (1,2,3,4,5,6) and (1,2,3,4,5,6)

  3. mathmath333
    • one year ago
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    is it 24/36=2/3

  4. anonymous
    • one year ago
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    you could just do \[\Pr(T>3)=1-\Pr(T \le3)\]

  5. anonymous
    • one year ago
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    would be less ways that way

  6. anonymous
    • one year ago
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    and you know there are 36 combinations in total for rolling any number.

  7. BAdhi
    • one year ago
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    yes chris is correct.. btw i forgot about (3,1), (4,1),... (3,2), (4,2),... combinations I think its better to follow chris 's way

  8. anonymous
    • one year ago
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    1,1 2,1 2,1 are the only combinations less than or equal to 3

  9. mathmath333
    • one year ago
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    is it 11/12

  10. anonymous
    • one year ago
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    \[\Pr(X \le3)=\frac{ 1 }{ 36 }+\frac{ 2 }{ 36 }\]

  11. anonymous
    • one year ago
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    ye

  12. anonymous
    • one year ago
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    looks good

  13. mathmath333
    • one year ago
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    11/12 is correct

  14. anonymous
    • one year ago
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    awesome

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