## mathmath333 one year ago Find the probablity that you get a total of more than 3 in a throw of 2 dice.

1. mathmath333

\large \color{black}{\begin{align} & \normalsize \text{ Find the probablity that you get a total of more than }\hspace{.33em}\\~\\ & \normalsize \text{ 3 in a throw of 2 dice .}\hspace{.33em}\\~\\ \end{align}}

more than 3 -> 6x4 (1,2,3,4,5,6) and (3,4,5,6) all the possibilites -> 6x6 (1,2,3,4,5,6) and (1,2,3,4,5,6)

3. mathmath333

is it 24/36=2/3

4. anonymous

you could just do $\Pr(T>3)=1-\Pr(T \le3)$

5. anonymous

would be less ways that way

6. anonymous

and you know there are 36 combinations in total for rolling any number.

yes chris is correct.. btw i forgot about (3,1), (4,1),... (3,2), (4,2),... combinations I think its better to follow chris 's way

8. anonymous

1,1 2,1 2,1 are the only combinations less than or equal to 3

9. mathmath333

is it 11/12

10. anonymous

$\Pr(X \le3)=\frac{ 1 }{ 36 }+\frac{ 2 }{ 36 }$

11. anonymous

ye

12. anonymous

looks good

13. mathmath333

11/12 is correct

14. anonymous

awesome