If the first child of a couple is a boy.Find the
probablity that the second child being a boy.

- mathmath333

If the first child of a couple is a boy.Find the
probablity that the second child being a boy.

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- mathmath333

\(\large \color{black}{\begin{align}
& \normalsize \text{ If the first child of a couple is a boy.Find the }\hspace{.33em}\\~\\
& \normalsize \text{probablity that the second child being a boy.}\hspace{.33em}\\~\\
\end{align}}\)

- anonymous

lol

- ParthKohli

Depending on one's interpretation of probability, the answer is either 1/2 or 1/3.

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## More answers

- AlexandervonHumboldt2

0? cause in a couple there is 1 girl and 1 boy if i remmeber correctly

- anonymous

hahaha

- anonymous

i think this type of question would not account for past results...

- anonymous

unless your a baby predictor

- ParthKohli

Read this: http://mathforum.org/dr.math/faq/faq.boygirl.choose.html

- ganeshie8

similar problem :
If you rolled a coin two times and if you saw HEAD first time, whats the probabiltiy that you see a HEAD on second roll too ?

- AlexandervonHumboldt2

hahah gane, i'm bad at prob, but i would say 0

- ParthKohli

@ganeshie8 What do you think the answer should be? 1/2?

- anonymous

is that called mutually exclusive? i forgot

- mathmath333

1/2

- AlexandervonHumboldt2

it can be 1/2 as well

- anonymous

what if you got con-joined twins one a female and the other a male

- anonymous

if thats ever possible

- ganeshie8

Yes, it has to be 1/2 if it is an unbiased coin; the coin has no memory, it wont remember the previous roll and decide itself to roll on a different face the next time

- mom.

1/3 (;

- ParthKohli

That's what I think too. However, this problem is a lot like the Monty Hall Problem, and given that one child is a boy, we eliminate the GG case, which leaves us with BG, GB, BB. That sounds like 1/3.

- ParthKohli

But again, it should be 1/2.

- mathmath333

It is from independent event problem

- AlexandervonHumboldt2

hmm bg=gb it is not said that the order is needed
i would say 1/2 or 0

- mom.

female gametes-->XX
male gametes --->XY
when u fuse u get either ----> XX or XY
so it will be 1/2

- ganeshie8

The probability would be different only if the experiment had already taken place, I think. Then, we can use Bayee inference and use conditional probability..

- ganeshie8

If the second coin is not rolled yet, then the probability of seeing HEAD on it is 1/2; this much is non negotiable.

- ganeshie8

On the other hand, if you have rolled the coins and had the results already, then the sample space is :
{HH, HT, TH, TT}
the probability would be 1/3; but clearly, in the main question the baby was not born yet, so the probabiblity for our main question should be 1/2.

- ParthKohli

Ohhh, so it's about an unborn baby.

- ParthKohli

Then definitely 1/2.

- ganeshie8

**
On the other hand, if you have rolled the coins and had the results already, then the sample space is :
{HH, HT, TH, TT}
If somebody tells you that one coin is H, the probability for other coin to be H would be 1/3; but clearly, in the main question the baby was not born yet, so the probabiblity for our main question should be 1/2.

- ParthKohli

If we're differentiating between the elder and the younger child, then 1/2 is surely the answer.

- mom.

(;

- AlexandervonHumboldt2

\(\Huge\color{black}{☺☻☺☻☺☻☺☻☺☻}\)

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