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mathmath333
 one year ago
If the first child of a couple is a boy.Find the
probablity that the second child being a boy.
mathmath333
 one year ago
If the first child of a couple is a boy.Find the probablity that the second child being a boy.

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mathmath333
 one year ago
Best ResponseYou've already chosen the best response.0\(\large \color{black}{\begin{align} & \normalsize \text{ If the first child of a couple is a boy.Find the }\hspace{.33em}\\~\\ & \normalsize \text{probablity that the second child being a boy.}\hspace{.33em}\\~\\ \end{align}}\)

ParthKohli
 one year ago
Best ResponseYou've already chosen the best response.1Depending on one's interpretation of probability, the answer is either 1/2 or 1/3.

AlexandervonHumboldt2
 one year ago
Best ResponseYou've already chosen the best response.20? cause in a couple there is 1 girl and 1 boy if i remmeber correctly

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i think this type of question would not account for past results...

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0unless your a baby predictor

ParthKohli
 one year ago
Best ResponseYou've already chosen the best response.1Read this: http://mathforum.org/dr.math/faq/faq.boygirl.choose.html

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.3similar problem : If you rolled a coin two times and if you saw HEAD first time, whats the probabiltiy that you see a HEAD on second roll too ?

AlexandervonHumboldt2
 one year ago
Best ResponseYou've already chosen the best response.2hahah gane, i'm bad at prob, but i would say 0

ParthKohli
 one year ago
Best ResponseYou've already chosen the best response.1@ganeshie8 What do you think the answer should be? 1/2?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0is that called mutually exclusive? i forgot

AlexandervonHumboldt2
 one year ago
Best ResponseYou've already chosen the best response.2it can be 1/2 as well

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0what if you got conjoined twins one a female and the other a male

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0if thats ever possible

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.3Yes, it has to be 1/2 if it is an unbiased coin; the coin has no memory, it wont remember the previous roll and decide itself to roll on a different face the next time

ParthKohli
 one year ago
Best ResponseYou've already chosen the best response.1That's what I think too. However, this problem is a lot like the Monty Hall Problem, and given that one child is a boy, we eliminate the GG case, which leaves us with BG, GB, BB. That sounds like 1/3.

ParthKohli
 one year ago
Best ResponseYou've already chosen the best response.1But again, it should be 1/2.

mathmath333
 one year ago
Best ResponseYou've already chosen the best response.0It is from independent event problem

AlexandervonHumboldt2
 one year ago
Best ResponseYou've already chosen the best response.2hmm bg=gb it is not said that the order is needed i would say 1/2 or 0

mom.
 one year ago
Best ResponseYou've already chosen the best response.2female gametes>XX male gametes >XY when u fuse u get either > XX or XY so it will be 1/2

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.3The probability would be different only if the experiment had already taken place, I think. Then, we can use Bayee inference and use conditional probability..

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.3If the second coin is not rolled yet, then the probability of seeing HEAD on it is 1/2; this much is non negotiable.

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.3On the other hand, if you have rolled the coins and had the results already, then the sample space is : {HH, HT, TH, TT} the probability would be 1/3; but clearly, in the main question the baby was not born yet, so the probabiblity for our main question should be 1/2.

ParthKohli
 one year ago
Best ResponseYou've already chosen the best response.1Ohhh, so it's about an unborn baby.

ParthKohli
 one year ago
Best ResponseYou've already chosen the best response.1Then definitely 1/2.

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.3** On the other hand, if you have rolled the coins and had the results already, then the sample space is : {HH, HT, TH, TT} If somebody tells you that one coin is H, the probability for other coin to be H would be 1/3; but clearly, in the main question the baby was not born yet, so the probabiblity for our main question should be 1/2.

ParthKohli
 one year ago
Best ResponseYou've already chosen the best response.1If we're differentiating between the elder and the younger child, then 1/2 is surely the answer.

AlexandervonHumboldt2
 one year ago
Best ResponseYou've already chosen the best response.2\(\Huge\color{black}{☺☻☺☻☺☻☺☻☺☻}\)
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