Help On Three Question Please!!!!!! Will Medal And Fan!

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- anonymous

Help On Three Question Please!!!!!! Will Medal And Fan!

- schrodinger

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- phi

I would plot the points, and connect the dots as a first step

- anonymous

ok like this?

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- phi

in a parallelogram, the opposite sides are equal. It is easy to find the length of the top and bottom sides (you count)
what do you get for the length of the top side?

- anonymous

6? on the top side.

- phi

yes, and 6 for the bottom also
for the "sides" you need to use the distance formula
do you know it?

- anonymous

Yes I Do

- phi

can you find the distance between (2,-2) and (5,3) ?

- anonymous

\[\sqrt{9+25}\]

- phi

yes, so \( \sqrt{34}\)

- anonymous

yes now what?

- phi

that is also the lenght of the other side
perimeter is the sum of the 4 lengths
\[ 6 + \sqrt{34}+ 6 + \sqrt{34}\]

- phi

you can combine "like terms" to make that a bit nicer

- anonymous

Wait so you add them?

- phi

yes, add the lengths. that is the definition of perimeter: total distance "around" the figure

- anonymous

\[12+\sqrt{68} \]

- phi

It is Greek: peri around, meter = measure or length

- phi

sqrt(a) + sqrt(a) is not the same as sqrt(2*a)
all you can do is say: I have one sqr(34) plus another sqr(34). How many sqr(34)'s do I have ?

- anonymous

2 sqrt(34) ?

- phi

yes
so
\[ 12 + 2\sqrt{34} \]
is the answer they want

- anonymous

ok so same on this one right?

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- phi

same idea, except opposite sides need not be equal , so it's more work
First plot the points to see "what is what"

- anonymous

So this?

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- phi

yes.
you can use the distance formula for all 4 sides, but for 3 of them, you can just count

- anonymous

So Top Side = 3
Bottom Side = 9
Right Side = 5

- phi

now the last side, you use the distance formula

- anonymous

\[\sqrt{36+25}\]

- phi

what do you get for the perimeter?

- anonymous

\[\sqrt{61}\]

- phi

that is the length of the 4th side. the perimeter is the sum of the 4 sides.

- phi

I assume you mean 17+sqr(61)

- anonymous

yes

- anonymous

so it is \[17+\sqrt{61}\]

- phi

yes

- anonymous

is that it?

- phi

yes, that is the perimeter of the figure, in "exact" form (we could change the sqr(61) to a decimal, but it would only be approximate)

- anonymous

This Last One

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- anonymous

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- anonymous

Top And Bottom are 7

- phi

yes, you can do these problems

- anonymous

\[\sqrt{25+64}\]

- anonymous

\[\sqrt{89} \] for both sides right and left

- anonymous

\[14+2\sqrt{89}\]

- phi

looks good

- anonymous

@phi you taught me how to do this!

- anonymous

Thanks!

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