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anonymous
 one year ago
can someone help me again cx?
simplify: a(x+y)a(xy)
(a) 2ax
(b) 2ay
(c) ax+ay
(d) 2ax2ay
anonymous
 one year ago
can someone help me again cx? simplify: a(x+y)a(xy) (a) 2ax (b) 2ay (c) ax+ay (d) 2ax2ay

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MrNood
 one year ago
Best ResponseYou've already chosen the best response.0you can tkae the factor 'a' out of each term and that leaves the following: a[(x+y)(xy)] work out the value inside the square brackets first....

MrNood
 one year ago
Best ResponseYou've already chosen the best response.0(x+y)(xy) what does this work out to be?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ughhhh idk :( i don't understand this math

MrNood
 one year ago
Best ResponseYou've already chosen the best response.0You never will unless you try (x+y)  (xy) =?? just be careful about the MINUS sign but work out that expression....

MrNood
 one year ago
Best ResponseYou've already chosen the best response.0@suppa_lova do not give direct answers  especially when they are wrong

MrNood
 one year ago
Best ResponseYou've already chosen the best response.0@suppa_lova You have not dealt correctly with the minus sign (as I warned above)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0did you factor in the a at the beginning of each
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