A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 one year ago
Using the completingthesquare method, rewrite f(x) = x2 − 8x + 3 in vertex form.
f(x) = (x − 8)^2
f(x) = (x − 4)^2 − 13
f(x) = (x − 4)^2 + 3
f(x) = (x − 4)^2 + 16
anonymous
 one year ago
Using the completingthesquare method, rewrite f(x) = x2 − 8x + 3 in vertex form. f(x) = (x − 8)^2 f(x) = (x − 4)^2 − 13 f(x) = (x − 4)^2 + 3 f(x) = (x − 4)^2 + 16

This Question is Closed

MrNood
 one year ago
Best ResponseYou've already chosen the best response.1well  you could expand all the answers and see which is the same as the original equation  but that is the long way round. Look at the brackets which are all 'squared' look at teh constant term (e.g. 8 in the first example) when you square brackets you will always get the square of that value as a constant so again in the first example you will get +64 as the constant when you expand now  you can see that that is NOT the same as the original (the constant is +3 in the original) So  go throught the answers and work out the resultant of the CONSTANT terms only. Only one of them works out to be +3 so that must be the answer

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Then wouln't it be the second one?

MrNood
 one year ago
Best ResponseYou've already chosen the best response.1However  that is a quick 'cheat' given that itis a multichoice question. To really complete your understanding you should use the 'compete the square' method as required by the question  if you didn't have the multichoice you would have to do that...
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.