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1Dfanatic

  • one year ago

You have a bag containing three red, seven green, and six blue pens. You choose tow pens at random. Find P(blue and blue) with replacing. Make sure to show/explain your work.

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  1. anonymous
    • one year ago
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    so let's see there are 16 pens.

  2. anonymous
    • one year ago
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    Choosing blue is 3/8 chance

  3. anonymous
    • one year ago
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    second time is 1/3

  4. anonymous
    • one year ago
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    multiply to find chance

  5. welshfella
    • one year ago
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    first find probability of drawing a blue on a single draw. since the 2 draws are independent the above probability is multiplied by itself to give the answer you want.

  6. anonymous
    • one year ago
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    The probability of picking two blue pens is approx 12.5%

  7. 1Dfanatic
    • one year ago
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    i got 1/3

  8. welshfella
    • one year ago
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    No the probabiluty of a second blue is also 3/8 because the ball is replaced.

  9. welshfella
    • one year ago
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    so P(blue and blue) = 3/8 * 3/8

  10. 1Dfanatic
    • one year ago
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    then it'd be 9/64

  11. welshfella
    • one year ago
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    yes

  12. 1Dfanatic
    • one year ago
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    thank you

  13. welshfella
    • one year ago
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    you understand why 1 draw = 3/8? 6 out of 16 = 3/8

  14. welshfella
    • one year ago
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    yw

  15. welshfella
    • one year ago
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    dahmanman would have been right if the ball was not replaced

  16. welshfella
    • one year ago
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    - because there would have been 5 blues out of a total of 15 balls, which = 1/3

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