Identifying parallel and perpendicular lines from coordinates...Help!

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- anonymous

Identifying parallel and perpendicular lines from coordinates...Help!

- schrodinger

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- anonymous

This is the one...

##### 1 Attachment

- anonymous

- anonymous

Do you know how to use this equation to find the slope of a line?\[m=\frac{ y_2-y_1 }{ x_2-x_1 }\]

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- anonymous

yes

- anonymous

great. you want to start by using that equation to get the slopes of the three lines

- anonymous

0/3 for the first one

- anonymous

I got
m = (8 - 2) /(-3 - 0) = 6/(-3) = -2

- anonymous

Its confusing

- anonymous

you have to enter the points into the equation|dw:1444407766451:dw|

- anonymous

oooohh i was doing something else but I understand now

- anonymous

then that reduces to \[m=\frac{ -6 }{ 3 }\]
\[m=-2\]

- anonymous

yeah so the first one is -2

- anonymous

yep. try the 2nd one

- anonymous

8/-4

- anonymous

yes and what does that reduce to?

- anonymous

2/1

- anonymous

-2 actually

- anonymous

now the third

- anonymous

ok 8/4 = 2

- anonymous

yep. ok so the three slopes are
line 1 = -2
line 2 = -2
line 3 = 2

- anonymous

for part b.
parallel lines have the same slope, so lines 1 and 2 are parallel
perpendicular lines have opposite reciprocal slopes. (like if one line has slope of 2, then the other must have slope of -½.) None of them are like that, so none of the lines are perpendicular

- anonymous

ok

- anonymous

@peachpi what about 6/9 , 2/-3 , 3/2

- anonymous

where did those numbers come from?

- anonymous

I did this one

##### 1 Attachment

- anonymous

- anonymous

ok. reduce the first one to 2/3.
for the 2nd one, once you're done with the math move the negative sign out front, so it's -2/3.
None of them are the same, so none are parallel.
2/3 and -3/2 have different signs, and are reciprocals (aka flipped over). so the lines with those two slope are perpendicular

- anonymous

oops. the 3/2 is positive, so it's perpendicular to the line with slope of -2/3.
That looks like lines 2 and 3 are perpendicular

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