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anonymous

  • one year ago

So I'm learning about motion problems that deal with distance, rate, and time. The formulas that are usually used are d=rt , r =d/t , or t=d/r. I need help with forming an equation for this problem: A boy leaves on a bicycle trip at the rate of 8 mph. One hour later the father, realizing that his son forgot his camping gear, sets out by car. How fast must the father drive to overtake the boy in 15 minutes?

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  1. ganeshie8
    • one year ago
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    Hint : By the time the father meets his son, both would have travelled the same distance.

  2. anonymous
    • one year ago
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    look you need to find the car's vilocity. lets write it as v you know that time in whihc father has to overtake the boy is 15 min so 15*v equals to the distance that boy (with vilocity 8mph) will drive in 1hour+15 min the distance that the boy will drive before his father overtake him is equal to (1h+1/4h)*8mph 1/4h is 15 min so here is our equation 1h*v=(1h+1/4h)*8mph

  3. anonymous
    • one year ago
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    just solve this one. do you need help with solving or you will do this task on your own?

  4. ganeshie8
    • one year ago
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    must be a typo i guess, it should be : 1/4h*v=(1h+1/4h)*8mph

  5. anonymous
    • one year ago
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    oops sorry. you are right @ganeshie8 . thanks for mentioning the mistake!

  6. anonymous
    • one year ago
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    I will be able to solve it myself, thank you so much for your input!

  7. anonymous
    • one year ago
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    nope :)

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