Destinyyyy
  • Destinyyyy
Help with a word problem..
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
katieb
  • katieb
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Destinyyyy
  • Destinyyyy
A rain gutter is made from sheets of aluminum that are 24 inches wide. The edges are turned up to form right angles. Determine the depth of the gutter that will allow a cross-sectional area of 58 square inches. There are two solutions to this problem. Round to the nearest tenth of an inch.
lolacole12
  • lolacole12
A rain gutter is made from sheets of aluminum that are 24 inches wide. The edges are turned up to form right angles. Determine the depth of the gutter that will allow a cross-sectional area of 58 square inches. There are two solutions to this problem. Round to the nearest tenth of an inch.
lolacole12
  • lolacole12
A rain gutter is made from sheets of aluminum that are 20 inches wide. The edges are turned up to form right angles. Determine the depth of the gutter that will allow a cross-sectional area of 13 square inches. Show that there are two different solutions to the problem. Round to the nearest tenth of an inch. : Let x = the depth of the gutter Let y = the width of the gutter : This may illustrate an end view of the gutter: x|_y_|x then 2x + y = 20 in; the width of the sheets of aluminum y = (20-2x); use this form for substitution and x*y = 13 sq/in; (the cross sectional area of the end of the gutter) : Using the area equation replace y with (20-2x) x*(20-2x) = 13 a quadratic equation -2x^2 + 20x - 13 = 0

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Destinyyyy
  • Destinyyyy
I got to.. -20+- square root 296 over -4

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