## TrojanPoem one year ago Engineering drawing.

1. TrojanPoem
2. TrojanPoem

@Michele_Laino

3. Michele_Laino

ok! let me think...

4. Michele_Laino

I know the position of this point: |dw:1444416115829:dw|

5. TrojanPoem

You know it, on the drawn figure, but if you are drawing it yourself, you don't :/

6. TrojanPoem

I have this part solved, but I can't grasp it , surely, you will.

7. Michele_Laino

I think that the equation below can solve your proble, please note trhat $$R_1=x$$ |dw:1444416517572:dw| so we can write this: ${\left( {120 + x} \right)^2} = {160^2} + {\left( {x + 20} \right)^2}$ namely, I have applied the theorem of Pitagora

8. Michele_Laino

I got: $$x=580/11$$

9. Michele_Laino

and, using my formula above, I got $$R_2=160/7$$

10. TrojanPoem

Yeah, You got the right radius but in Engineering drawing, I can't write steps of getting them so , I'd be considered cheater

11. Michele_Laino

I see, nevertheless when you go in laboratory, in order to manufacture your object, you have to provide to the worker the measures of the radiuses

12. TrojanPoem

Lab ? is this used in physics too ?

13. Michele_Laino

sorry, I meant in mechanical workshop

14. TrojanPoem

I think redraw this figures is just to prepare us to draw object parts

15. Michele_Laino

yes I think so!