TrojanPoem
  • TrojanPoem
Engineering drawing.
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
TrojanPoem
  • TrojanPoem
http://assets.openstudy.com/updates/attachments/5617ae72e4b07ab19da6964e-trojanpoem-1444392654289-033.jpg
TrojanPoem
  • TrojanPoem
@Michele_Laino
Michele_Laino
  • Michele_Laino
ok! let me think...

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

Michele_Laino
  • Michele_Laino
I know the position of this point: |dw:1444416115829:dw|
TrojanPoem
  • TrojanPoem
You know it, on the drawn figure, but if you are drawing it yourself, you don't :/
TrojanPoem
  • TrojanPoem
I have this part solved, but I can't grasp it , surely, you will.
Michele_Laino
  • Michele_Laino
I think that the equation below can solve your proble, please note trhat \(R_1=x\) |dw:1444416517572:dw| so we can write this: \[{\left( {120 + x} \right)^2} = {160^2} + {\left( {x + 20} \right)^2}\] namely, I have applied the theorem of Pitagora
Michele_Laino
  • Michele_Laino
I got: \(x=580/11\)
Michele_Laino
  • Michele_Laino
and, using my formula above, I got \(R_2=160/7\)
TrojanPoem
  • TrojanPoem
Yeah, You got the right radius but in Engineering drawing, I can't write steps of getting them so , I'd be considered cheater
2 Attachments
Michele_Laino
  • Michele_Laino
I see, nevertheless when you go in laboratory, in order to manufacture your object, you have to provide to the worker the measures of the radiuses
TrojanPoem
  • TrojanPoem
Lab ? is this used in physics too ?
Michele_Laino
  • Michele_Laino
sorry, I meant in mechanical workshop
TrojanPoem
  • TrojanPoem
I think redraw this figures is just to prepare us to draw object parts
Michele_Laino
  • Michele_Laino
yes I think so!

Looking for something else?

Not the answer you are looking for? Search for more explanations.