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TrojanPoem

  • one year ago

Engineering drawing.

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  1. TrojanPoem
    • one year ago
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    @Michele_Laino

  2. Michele_Laino
    • one year ago
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    ok! let me think...

  3. Michele_Laino
    • one year ago
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    I know the position of this point: |dw:1444416115829:dw|

  4. TrojanPoem
    • one year ago
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    You know it, on the drawn figure, but if you are drawing it yourself, you don't :/

  5. TrojanPoem
    • one year ago
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    I have this part solved, but I can't grasp it , surely, you will.

  6. Michele_Laino
    • one year ago
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    I think that the equation below can solve your proble, please note trhat \(R_1=x\) |dw:1444416517572:dw| so we can write this: \[{\left( {120 + x} \right)^2} = {160^2} + {\left( {x + 20} \right)^2}\] namely, I have applied the theorem of Pitagora

  7. Michele_Laino
    • one year ago
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    I got: \(x=580/11\)

  8. Michele_Laino
    • one year ago
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    and, using my formula above, I got \(R_2=160/7\)

  9. TrojanPoem
    • one year ago
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    Yeah, You got the right radius but in Engineering drawing, I can't write steps of getting them so , I'd be considered cheater

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  10. Michele_Laino
    • one year ago
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    I see, nevertheless when you go in laboratory, in order to manufacture your object, you have to provide to the worker the measures of the radiuses

  11. TrojanPoem
    • one year ago
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    Lab ? is this used in physics too ?

  12. Michele_Laino
    • one year ago
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    sorry, I meant in mechanical workshop

  13. TrojanPoem
    • one year ago
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    I think redraw this figures is just to prepare us to draw object parts

  14. Michele_Laino
    • one year ago
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    yes I think so!

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