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anonymous
 one year ago
If x=cost and y=tant, how do I get rid of the parameter?
anonymous
 one year ago
If x=cost and y=tant, how do I get rid of the parameter?

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welshfella
 one year ago
Best ResponseYou've already chosen the best response.1if y is the tangent of t then t is the angle whose tangent is y so we can write t = tan1 y or t = arctan y do a similar procedure with y = cos t then you can form a relation between x and y

Kainui
 one year ago
Best ResponseYou've already chosen the best response.1I'd do it this way: \[y=\tan t = \frac{ \sin t}{\cos t}\] Now we know we can plug in \(\cos t =x\) but what about the \(\sin t\) part? Well here's a trick, use the Pythagorean identity: \[\sin^2 t + \cos^2 t = 1\] We can rearrange to get: \[\sin t = \sqrt{1 x^2}\] So now we can finish plugging in: \[y= \frac{ \sin t}{\cos t} = \frac{\sqrt{1x^2}}{x}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0is + or  not necessary here? for the Square Root

welshfella
 one year ago
Best ResponseYou've already chosen the best response.1I think not because the angles are considered to be only in the first quadrant

Kainui
 one year ago
Best ResponseYou've already chosen the best response.1Oh yeah I think \(\pm\) is a good idea @ArkGoLucky

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Could you help me with one more problem while you are here?
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