anonymous
  • anonymous
If x=cost and y=tant, how do I get rid of the parameter?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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welshfella
  • welshfella
if y is the tangent of t then t is the angle whose tangent is y so we can write t = tan-1 y or t = arctan y do a similar procedure with y = cos t then you can form a relation between x and y
Kainui
  • Kainui
I'd do it this way: \[y=\tan t = \frac{ \sin t}{\cos t}\] Now we know we can plug in \(\cos t =x\) but what about the \(\sin t\) part? Well here's a trick, use the Pythagorean identity: \[\sin^2 t + \cos^2 t = 1\] We can rearrange to get: \[\sin t = \sqrt{1- x^2}\] So now we can finish plugging in: \[y= \frac{ \sin t}{\cos t} = \frac{\sqrt{1-x^2}}{x}\]
anonymous
  • anonymous
is + or - not necessary here? for the Square Root

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welshfella
  • welshfella
I think not because the angles are considered to be only in the first quadrant
Kainui
  • Kainui
Oh yeah I think \(\pm\) is a good idea @ArkGoLucky
anonymous
  • anonymous
Oh okay. Thanks.
anonymous
  • anonymous
Could you help me with one more problem while you are here?
anonymous
  • anonymous
Well either of you

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