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vera_ewing

  • one year ago

Math question

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  1. vera_ewing
    • one year ago
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  2. welshfella
    • one year ago
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    differentiate and equate to zero to find the turning points

  3. Michele_Laino
    • one year ago
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    furthermore the first derivative of your function is: \[f'\left( x \right) = 9{x^2} - 16\]

  4. anonymous
    • one year ago
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    円の円周は直径として直接変化します。円は60フィートの直径と188.4フィートの円周を持っています。 15フィートの直径とする円の円周は何ですか? 47.1フィート 7.5フィート 57.1フィート

  5. Michele_Laino
    • one year ago
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    your function is an increasing function if the subsequent condition holds: \[9{x^2} - 16 > 0\]

  6. Michele_Laino
    • one year ago
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    please solve that inequality

  7. vera_ewing
    • one year ago
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    9x^2-16>0 9x^2>0+16 9x^2>16 x>4/3

  8. ribhu
    • one year ago
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    not this way...

  9. ribhu
    • one year ago
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    find two solution.. square root is written with positive and negative sign...

  10. freckles
    • one year ago
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    what's up with those subscripts being x?

  11. Michele_Laino
    • one year ago
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    we can rewrite that inequality as below: \[\left( {3x - 4} \right)\left( {3x + 4} \right) > 0\] so the starting inequality is equivalent to the subsequent two systems of inequalities: \[\left\{ \begin{gathered} 3x - 4 > 0 \hfill \\ 3x + 4 > 0 \hfill \\ \end{gathered} \right.,\quad \left\{ {\begin{array}{*{20}{c}} {3x - 4 < 0} \\ {3x + 4 < 0} \end{array}} \right.\] please solve them

  12. welshfella
    • one year ago
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    you could have also have found the turning points and their nature and drawn a rough graph which might have looked like |dw:1444420588420:dw|

  13. welshfella
    • one year ago
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    then the increasing/ decreasing intervals can be seen from the graph.

  14. vera_ewing
    • one year ago
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    Ok so it's D?

  15. Michele_Laino
    • one year ago
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    i'm sorry option D is a wrong option

  16. anonymous
    • one year ago
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    what is 9+9

  17. vera_ewing
    • one year ago
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    Ok so it has to be B?

  18. Michele_Laino
    • one year ago
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    correct!

  19. vera_ewing
    • one year ago
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    Ok, thank you Michele!!!

  20. Michele_Laino
    • one year ago
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    :)

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