Math question

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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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differentiate and equate to zero to find the turning points
furthermore the first derivative of your function is: \[f'\left( x \right) = 9{x^2} - 16\]

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円の円周は直径として直接変化します。円は60フィートの直径と188.4フィートの円周を持っています。 15フィートの直径とする円の円周は何ですか? 47.1フィート 7.5フィート 57.1フィート
your function is an increasing function if the subsequent condition holds: \[9{x^2} - 16 > 0\]
please solve that inequality
9x^2-16>0 9x^2>0+16 9x^2>16 x>4/3
not this way...
find two solution.. square root is written with positive and negative sign...
what's up with those subscripts being x?
we can rewrite that inequality as below: \[\left( {3x - 4} \right)\left( {3x + 4} \right) > 0\] so the starting inequality is equivalent to the subsequent two systems of inequalities: \[\left\{ \begin{gathered} 3x - 4 > 0 \hfill \\ 3x + 4 > 0 \hfill \\ \end{gathered} \right.,\quad \left\{ {\begin{array}{*{20}{c}} {3x - 4 < 0} \\ {3x + 4 < 0} \end{array}} \right.\] please solve them
you could have also have found the turning points and their nature and drawn a rough graph which might have looked like |dw:1444420588420:dw|
then the increasing/ decreasing intervals can be seen from the graph.
Ok so it's D?
i'm sorry option D is a wrong option
what is 9+9
Ok so it has to be B?
correct!
Ok, thank you Michele!!!
:)

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