anonymous
  • anonymous
A company dyes two sizes of rugs. A small rug requires 4 hours for dyeing and a medium-size rug requires 6 hours for dyeing. The dyers have to make at least 20 rugs, and they must do it in less than 120 hours. Let x equal small rugs and y equal medium rugs. Which of the following inequalities can be paired with x + y ≥ 20 to create a system that represents this situation? 6x + 4y < 120 4x + 6y < 120 6x + 4y > 120 4x + 6y > 120
Algebra
jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
B.) 4x + 6y < 120
anonymous
  • anonymous
explain please @PrincessHush
anonymous
  • anonymous
Okay, this is the most easiest problem I've ever encountered. It says " Let x equal small rugs and y equal medium rugs. " "A small rug requires 4 hours for dyeing and a medium-size rug requires 6 hours for dyeing" That's where i got the 4x + 6y ≤ less than ≥ greater than and they must do it in LESS than 120 hours. That's where i got 4x + 6y < 20

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anonymous
  • anonymous
Nvm I See Why , Thank You Can You Help With Another?
anonymous
  • anonymous
It was just common sense xD @BrianaNicole16 but sure!(:

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