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shesolitt

  • one year ago

As shown below, an observer (O) is located 660 feet from a tree (T). The observer notices a hawk (H) flying at a 35° angle of elevation from his line of sight. What equation and trigonometric function can be used to solve for the height (h) of the hawk? What is the height of the hawk? You must show all work and calculations to receive full credit.

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  1. shesolitt
    • one year ago
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  2. shesolitt
    • one year ago
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    @thomas5267

  3. shesolitt
    • one year ago
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    plsss help me today lol as in rn i would really love to turn it in asap. im already a fan of you but ill medal you as well.

  4. thomas5267
    • one year ago
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    Do you remember the trig functions and their definition?

  5. shesolitt
    • one year ago
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    yes they relate the angles of a triangle to the lengths of its sides

  6. shesolitt
    • one year ago
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    @thomas5267

  7. thomas5267
    • one year ago
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    Could you name them?

  8. thomas5267
    • one year ago
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    And give the definition?

  9. shesolitt
    • one year ago
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    right triangle? @thomas5267

  10. shesolitt
    • one year ago
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    actually is it sin,cosine and tangent

  11. thomas5267
    • one year ago
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    Yes this is a right triangle. It looks like a right triangle and I will assume the tree grow straight lol.

  12. shesolitt
    • one year ago
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    lol oksay so what do i do after that @thomas5267

  13. thomas5267
    • one year ago
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    One of the trig function can be applied here. The question is which one.

  14. shesolitt
    • one year ago
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    one of the trig functions as in sin or cosine or tangent ? @thomas5267

  15. shesolitt
    • one year ago
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    im sorry im bad at geo

  16. thomas5267
    • one year ago
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    Yes. sin, cos, or tan.

  17. shesolitt
    • one year ago
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    how do i know which one it is @thomas5267 lol cus i dont

  18. thomas5267
    • one year ago
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    \[ \sin(\theta)=\frac{\text{opposite}}{\text{hypotenuse}}\\ \cos(\theta)=\frac{\text{adjacent}}{\text{hypotenuse}}\\ \tan(\theta)=\frac{\text{opposite}}{\text{adjacent}} \]

  19. thomas5267
    • one year ago
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    |dw:1444425795313:dw|

  20. thomas5267
    • one year ago
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    Hypotenuse is independent of which angle you choose. Adjacent and opposite however do. Note that you cannot choose the right angle to use the trig functions.

  21. thomas5267
    • one year ago
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    Hypotenuse is the side that is longest and is opposite to the right angle. Using the opposite to right angle definition is safer since in exams those teachers could trick you and draw a triangle not to scale.

  22. thomas5267
    • one year ago
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    |dw:1444425945588:dw|

  23. thomas5267
    • one year ago
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    Take a guess?

  24. shesolitt
    • one year ago
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    so the function is sin? @thomas5267

  25. shesolitt
    • one year ago
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    because it says hypotenuse over opposite

  26. thomas5267
    • one year ago
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    Think of what do you have and what do you want.

  27. thomas5267
    • one year ago
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    You have the distance to the tree and you want the height of the hawk.

  28. shesolitt
    • one year ago
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    im still confused lol im sorry /: @thomas5267

  29. shesolitt
    • one year ago
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    so how would i find the hawk do i use the distance formula

  30. shesolitt
    • one year ago
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    for the height of the hawk

  31. thomas5267
    • one year ago
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    \[\tan(\theta)\] Any ideas?

  32. shesolitt
    • one year ago
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    no ): still.. @thomas5267

  33. thomas5267
    • one year ago
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    \[ \tan(\theta)=\frac{\text{opposite}}{\text{adjacent}}\\ (\text{adjacent})\tan(\theta)=\frac{\text{opposite}}{\text{adjacent}}\text{adjacent}\\ (\text{adjacent})\tan(\theta)=\text{opposite} \]

  34. shesolitt
    • one year ago
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    so the function would be tan

  35. shesolitt
    • one year ago
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    how do i write an equation @thomas5267

  36. thomas5267
    • one year ago
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    \[ \theta=35\deg\\ \text{adjacent}=660\text{ ft} \] All given in the picture.

  37. shesolitt
    • one year ago
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    yes that helps lol thanks

  38. shesolitt
    • one year ago
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    so for the height i divide 660/35 @thomas5267

  39. thomas5267
    • one year ago
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    You want \(660\tan(35\deg)\).

  40. thomas5267
    • one year ago
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    |dw:1444427723299:dw|

  41. shesolitt
    • one year ago
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    so....an(35)=h660 h=660×tan(35) then i calculate the value of h @thomas5267

  42. thomas5267
    • one year ago
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    Yep.

  43. shesolitt
    • one year ago
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    thank youuuuu lol i get it now !. so thats all i should write? @thomas5267

  44. thomas5267
    • one year ago
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    Yep. You can get \(\tan(35\deg)\) using calculator. Make sure the calculator is using degree mode.

  45. shesolitt
    • one year ago
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    i got 0.7 @thomas5267

  46. shesolitt
    • one year ago
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    or is it 462.14

  47. shesolitt
    • one year ago
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    thats my final answer @thomas5267

  48. thomas5267
    • one year ago
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    Yes, but why do you need to state the complementary angle? It is not ask in the question right? \[ \tan(35\deg)=0.7020754 \]

  49. shesolitt
    • one year ago
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    thank you soooo muchhhh (:::

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