anonymous
  • anonymous
Determine whether the origin is included in the shaded region and whether the shaded region is above or below the line for the graph of the following inequality: y > three fifthsx − 2 The origin is not included in the shaded region and the shaded area is above the line. The origin is not included in the shaded region and the shaded area is below the line. The origin is included in the shaded region and the shaded area is above the line. The origin is included in the shaded region and the shaded area is below the line.
Algebra
  • Stacey Warren - Expert brainly.com
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SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
schrodinger
  • schrodinger
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welshfella
  • welshfella
|dw:1444427046937:dw|
anonymous
  • anonymous
thats the answer?
welshfella
  • welshfella
that is a rough drawing of the the line whose equation is y = (3/5)x - 2

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More answers

welshfella
  • welshfella
the inequality is 'above' that line as its y > (3/5)x - 2
welshfella
  • welshfella
that info should give you the correct option
anonymous
  • anonymous
ok so it would be A ? @welshfella
anonymous
  • anonymous
@imqwerty is this A?
imqwerty
  • imqwerty
no
welshfella
  • welshfella
No not A Look where the origin is with respect to the line above or below?
welshfella
  • welshfella
> = above
anonymous
  • anonymous
ok so it would be C?
imqwerty
  • imqwerty
yes :)
welshfella
  • welshfella
yep
anonymous
  • anonymous
ok thank u both

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