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Destinyyyy

  • one year ago

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  1. Destinyyyy
    • one year ago
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    Solve. An investment is worth $3486 in 1995. By 2000 it has grown to $6441. Let y be the value of the investment in the year x, where x = 0 represents 1995. Write a linear equation that models the value of the investment in the year x.

  2. Destinyyyy
    • one year ago
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    @jim_thompson5910

  3. jim_thompson5910
    • one year ago
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    `x = 0 represents 1995` in the year 2000, what is x?

  4. Destinyyyy
    • one year ago
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    x is 5

  5. jim_thompson5910
    • one year ago
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    yes

  6. jim_thompson5910
    • one year ago
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    `An investment is worth $3486 in 1995` x = 0 and y = 3486 the point (0,3486) is on the graph

  7. jim_thompson5910
    • one year ago
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    `By 2000 it has grown to $6441` the point (5,6441) is on the graph

  8. jim_thompson5910
    • one year ago
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    use the slope formula to find the slope through (0,3486) and (5,6441).

  9. Destinyyyy
    • one year ago
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    Okay.

  10. Destinyyyy
    • one year ago
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    591

  11. jim_thompson5910
    • one year ago
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    yes

  12. jim_thompson5910
    • one year ago
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    m = 591 is the slope b = 3486 since we know (0,3486) is on the graph

  13. jim_thompson5910
    • one year ago
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    plug those into y = mx+b

  14. Destinyyyy
    • one year ago
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    The equation is y=591x+3486

  15. jim_thompson5910
    • one year ago
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    yes

  16. Destinyyyy
    • one year ago
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    Okay. One more.

  17. Destinyyyy
    • one year ago
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    38. Find the domain of the indicated combined function. Find the domain of (fg)(x) when f(x) = square root 5x+8 and g(x) = .square root 7x-9

  18. Destinyyyy
    • one year ago
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    Ive never done a problem like this with square root so im not sure where to start

  19. Destinyyyy
    • one year ago
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    Normally id plug them in next to each other and multiple.

  20. jim_thompson5910
    • one year ago
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    first solve 5x+8 >= 0 for x

  21. Destinyyyy
    • one year ago
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    x>/ -8/5

  22. jim_thompson5910
    • one year ago
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    type `>=` to mean "greater than or equal to"

  23. jim_thompson5910
    • one year ago
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    I agree, it's `x >= -8/5`

  24. jim_thompson5910
    • one year ago
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    now solve `7x-9 > 0` for x

  25. Destinyyyy
    • one year ago
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    9/7

  26. jim_thompson5910
    • one year ago
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    there is NO underline because we don't want 7x-9 to be 0

  27. jim_thompson5910
    • one year ago
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    `x > 9/7` I think you mean

  28. jim_thompson5910
    • one year ago
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    plot `x >= -8/5` and `x > 9/7` on the same number line then shade the region where they both overlap

  29. Destinyyyy
    • one year ago
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    Yes.

  30. Destinyyyy
    • one year ago
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    The domain is [9/7 , infinity)

  31. jim_thompson5910
    • one year ago
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    if x = 9/7, then the denominator would be 0. But we cannot divide by 0

  32. Destinyyyy
    • one year ago
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    Um okay..

  33. jim_thompson5910
    • one year ago
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    so we have to kick out 9/7 from the domain

  34. Destinyyyy
    • one year ago
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    [0,infinity)

  35. jim_thompson5910
    • one year ago
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    you were on the right track, just change the `[` to `(`

  36. jim_thompson5910
    • one year ago
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    Domain: `(9/7, infinity)`

  37. Destinyyyy
    • one year ago
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    I only have options of- [9/7, infinity) [0,infinity)

  38. jim_thompson5910
    • one year ago
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    hmm so strange. That has to be a typo because 9/7 isn't part of the domain

  39. jim_thompson5910
    • one year ago
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    oh wait, it's (fg)(x) and not (f/g)(x) so yeah 9/7 is allowed

  40. Destinyyyy
    • one year ago
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    Okay. Thank you.

  41. jim_thompson5910
    • one year ago
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    no problem

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