nonopro one year ago Lucas cut a board that was 3 1/5 in. long and 3 1/3 in. wide. What was the area of the board? Express your answer in simplest form. A.15 1/5 in² B.10 2/3 in² C.9 2/5 in² D.6 8/15 in²

1. anonymous

$$\color {olive} {\text{First know the formula of Area of a Rectangle:}}$$ $$A=length \times width$$ $$\color {olive} {\text{Change the the given (mixed numbers) to improper fractions:}}$$ $$l=3\frac{1}{5} \rightarrow \frac{16}{5}$$ $$w=3\frac{1}{3} \rightarrow \frac{10}{3}$$ $$\color {olive} {\text{Plug in the formula the given:}}$$ $$\color {indigo} {\text{GIVEN:}}$$ $$l=\frac{16}{5}$$ $$w=\frac{10}{3}$$ $$\huge A=\frac{16}{5} \times \frac{10}{3}$$ $$\color {olive} {\text{Multiply the numerators and denominators:}}$$ $$\huge A=\frac{16}{5} \times \frac{10}{3} =\frac{16 \times 10}{5 \times 3}=\frac {160}{15}$$

2. anonymous

well, is a board, so I assume a rectangle thus area of a rectangle = length * width multiply the given measures

3. anonymous

$$\color {olive} {\text{Now simplify}\huge \frac{160}{15}}.$$ |dw:1444430278831:dw|

4. anonymous

$$\color {olive} {\text{Then change the improper fraction to a mixed number:}}$$ |dw:1444430410002:dw|