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nonopro
 one year ago
Lucas cut a board that was 3 1/5 in. long and 3 1/3 in. wide.
What was the area of the board?
Express your answer in simplest form.
A.15 1/5
in²
B.10 2/3
in²
C.9 2/5
in²
D.6 8/15
in²
nonopro
 one year ago
Lucas cut a board that was 3 1/5 in. long and 3 1/3 in. wide. What was the area of the board? Express your answer in simplest form. A.15 1/5 in² B.10 2/3 in² C.9 2/5 in² D.6 8/15 in²

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\(\color {olive} {\text{First know the formula of Area of a Rectangle:}}\) \(A=length \times width\) \(\color {olive} {\text{Change the the given (mixed numbers) to improper fractions:}}\) \(l=3\frac{1}{5} \rightarrow \frac{16}{5}\) \(w=3\frac{1}{3} \rightarrow \frac{10}{3}\) \(\color {olive} {\text{Plug in the formula the given:}}\) \(\color {indigo} {\text{GIVEN:}}\) \(l=\frac{16}{5}\) \(w=\frac{10}{3}\) \(\huge A=\frac{16}{5} \times \frac{10}{3}\) \(\color {olive} {\text{Multiply the numerators and denominators:}}\) \(\huge A=\frac{16}{5} \times \frac{10}{3} =\frac{16 \times 10}{5 \times 3}=\frac {160}{15}\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0well, is a board, so I assume a rectangle thus area of a rectangle = length * width multiply the given measures

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\(\color {olive} {\text{Now simplify}\huge \frac{160}{15}}.\) dw:1444430278831:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\(\color {olive} {\text{Then change the improper fraction to a mixed number:}}\) dw:1444430410002:dw
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