Five people want to rent the last two copies of a movie. How many ways can these five people rent the two movies? A. 10 B. 9 C. 8 D. 7 E. 6

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Five people want to rent the last two copies of a movie. How many ways can these five people rent the two movies? A. 10 B. 9 C. 8 D. 7 E. 6

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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Take 5 people and group them into two groups, one of size 2 (the ones that get the copies) and the other of size 3 (the ones that don't get the copies): $$ {{5}\choose{2}}=\cfrac{5!}{2!3!} $$ This is because there are 5! ways to permute the 5 people, but 2! of them are the same combination, just in different order and similarly for the 3! of the second group. Does this make sense?
ohh i get it now so the answer is 10?
yes!

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The answer is, "A". 10.
whoops he already answered you. Sorry!

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